"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
assert square_Sum(2) == 10
"""
def square_Sum(n):
return n * (4 * n * n - 1) / 3
[[2], [3], [4]] [[1000000.0], [10000000.0], [100000000.0], [1], [10], [100], [123456789], [999999999], [5], [7], [15], [50000], [999999], [1234567890], [3], [4], [2], [3], [4], [14], [8], [6], [9], [16], [1000000000], [999999998], [95], [13], [123456788], [101], [123456787], [17], [True], [12], [89], [1234567891], [102], [90], [1000000001], [88], [26], [1000000], [98], [96], [23], [24], [103], [25], [91], [1234567889], [1000000002], [27], [1000000003], [11], [97], [999998], [18], [50002], [104], [99], [1000000004], [49999], [50001], [19], [94], [93], [22], [20], [1234567892], [74], [59], [92], [28], [77], [1000001], [58], [999997], [999996], [75], [999999997], [60], [123456790], [50003], [50004], [87], [78], [76], [999995], [21], [999994], [50005], [123456791], [29], [85], [73], [49998], [50006], [123456792], [1234567888], [999999996], [57], [1234567893], [86], [84], [1234567887], [83], [50007], [49997], [79], [30], [50008], [31], [64], [105], [1234567886], [61], [62], [1234567885], [999999994]] code-llama-multi-7b. fail_base: True, fail_plus: True
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
assert square_Sum(2) == 10
"""
def square_Sum(n):
"""
:param n: int
:return: int
"""
if n < 1:
return 0
else:
return sum(i ** 2 for i in range(1, n + 1, 2))
if __name__ == '__main__':
print(square_Sum(2))
print(square_Sum(3))
print(square_Sum(4))
print(square_Sum(5))
print(square_Sum(6))
print(square_Sum(7))
print(square_Sum(8))
print(square_Sum(9))
print(square_Sum(10))
print(square_Sum(11))
print(square_Sum(12))
print(square_Sum(13))
print(square_Sum(14))
print(square_Sum(15))
print(square_Sum(16))
print(square_Sum(17))
print(square_Sum(18))
print(square_Sum(19))
print(square_Sum(20))
print(square_Sum(21))
print(square_Sum(22))
print(square_Sum(23))
print(square_Sum(24))
print(square_Sum(25))
print(square_Sum(26))
print(square_Sum(27))
print(square_Sum(28))
print(square_Sum(29))
print(square_Sum(30))
print(square_Sum(31))
print(square_Sum(32))
print(square_Sum(33))
print(square_Sum(34))
print(square_Sum(35))
print(square_Sum(36))
print(square_Sum(37))
print(square_Sum(38))
print(square_Sum(39))
print(square_Sum(40))
print(square_Sum(4databricks--dbrx-instruct. fail_base: True, fail_plus: True
def square_sum(n):
"""
This function takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
"""
total = 0
for i in range(1, 2 * n + 1, 2):
total += i ** 2
return total
# Test the function
assert square_sum(2) == 10CohereForAI--c4ai-command-r-plus. fail_base: False, fail_plus: True
def square_Sum(n):
return sum([(2 * i - 1) ** 2 for i in range(1, n + 1)])
```claude-3-haiku-20240307. fail_base: False, fail_plus: True
Here's the solution wrapped in a Python markdown block:
```python
def square_Sum(n):
"""
Calculates the sum of the squares of the first n odd natural numbers.
Args:
n (int): The number of odd natural numbers to consider.
Returns:
int: The sum of the squares of the first n odd natural numbers.
"""
total = 0
for i in range(1, 2*n, 2):
total += i**2
return total
# Test the function
assert square_Sum(2) == 10code-millenials-34b. fail_base: False, fail_plus: True
def square_Sum(n):
sum_squares = 0
for i in range(1, 2*n, 2):
sum_squares += i**2
return sum_squares
# Test the function
assert square_Sum(2) == 10dolphin-2.6. fail_base: True, fail_plus: True
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
assert square_Sum(2) == 10
"""
def square_sum(n):
sum = 0
for i in range(1, 2*n, 2):
sum += i**2
return sum
# Test the function
assert square_Sum(2) == 10claude-3-opus-20240229. fail_base: False, fail_plus: True
Here's the solution to the problem, wrapped in a markdown block:
```python
def square_Sum(n):
"""
Returns the sum of the squares of the first n odd natural numbers.
"""
return sum(i**2 for i in range(1, 2*n, 2))mixtral-8x7b-instruct. fail_base: False, fail_plus: True
def square_Sum(n):
# Initialize sum variable
sum = 0
# Iterate over the first n odd natural numbers
for i in range(1, 2*n, 2):
# Add the square of the current number to the sum
sum += i**2
# Return the final sum
return sum
# Assert the function works as expected
assert square_Sum(2) == 10wizardcoder-34b. fail_base: False, fail_plus: True
Here's the Python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers:
```python
def square_Sum(n):
sum = 0
for i in range(1, 2*n, 2):
sum += i**2
return sum
```
Explanation:
- We initialize a variable `sum` to 0 to store the sum of the squares of the first n odd natural numbers.
- We use a for loop to iterate from 1 to 2*n with a step of 2, since we only want to consider odd numbers.
- We add the square of each odd number to the `sum` variable.
- Finally, we return the `sum` variable.
For example, if `n=2`, the function will iterate from 1 to 3 (since 2 is the first odd number) and add 1^2 and 3^2 to the `sum` variable, which is 1+9=10. Therefore, the function will return 10. mixtral-8x22b-instruct-v0.1. fail_base: True, fail_plus: True
def square_sum(n):
"""
This function takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
"""
return sum((2 * i - 1) ** 2 for i in range(1, n + 1))
# Test the function
assert square_sum(2) == 10
print("All test cases pass")code-llama-multi-34b. fail_base: True, fail_plus: True
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
assert square_Sum(2) == 10
"""
def square_Sum(n):
sum = 0
for i in range(1, n+1):
if i % 2 != 0:
sum += i**2
return sum
print(square_Sum(2))
Qwen--Qwen1.5-72B-Chat. fail_base: False, fail_plus: True
def square_Sum(n):
"""
This function takes an integer n and returns the sum of the squares of the first n odd natural numbers.
"""
return sum(i**2 for i in range(1, 2*n, 2))
# Test cases
assert square_Sum(2) == 10
assert square_Sum(3) == 25
assert square_Sum(4) == 45
assert square_Sum(5) == 85mistral-large-latest. fail_base: True, fail_plus: True
Sure, here's a Python function that solves the problem:
```python
def square_sum(n):
"""
This function takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
"""
sum = 0
i = 1
while n > 0:
sum += i * i
i += 2
n -= 1
return sum
# Test the function
assert square_sum(2) == 10
```
This function uses a while loop to iterate through the first `n` odd numbers, squares each one, and adds it to a running total. The variable `i` is initialized to 1 (the first odd number) and is incremented by 2 in each iteration of the loop to ensure that it only considers odd numbers.codegen-2b. fail_base: True, fail_plus: True
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
assert square_Sum(2) == 10
"""
def square_Sum(n):
sum = 0
for i in range(1,n+1):
if i%2!= 0:
sum += i**2
return sum
assert square_Sum(2) == 10
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n even natural numbers.
assert square_Sum(2) == 4
"""
def square_Sum(n):
sum = 0
for i in range(1,n+1):
if i%2 == 0:
sum += i**2
return sum
assert square_Sum(2) == 4
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n natural numbers.
assert square_Sum(2) == 4
"""
def square_Sum(n):
sum = 0
for i in range(1,n+1):
sum += i**2
return sum
assert square_Sum(2) == 4
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n natural numbers.
assert square_Sum(2) == 4
"""
def square_Sum(n):
sum = 0
for i in range(1,n+1):
sum += i**2
return sum
assert square_Sum(2) == 4
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n natural numbers.
assert square_Sum(2) == 4
"""
def square_Sum(n):
sum = 0
for i in range(1,n+1):
sum += i**2
return sum
assert square_Sum(2) == 4
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n natural numbers.
assert square_Sum(2) == 4
"""
def square_Sum(n):
sum = 0
for i in range(1,n+1):
sum += i**2
return sum
assert square_Sum(2) == 4HuggingFaceH4--starchat2-15b-v0.1. fail_base: True, fail_plus: True
def square_sum(n):
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
assert square_sum(2) == 10
"""
# The sum of the squares of the first n odd numbers can be calculated using the formula: n*(4*n^2 - 1)/3
return n * (4 * n**2 - 1) // 3
# Test the function
assert square_sum(2) == 10
assert square_sum(3) == 36
assert square_sum(5) == 140
assert square_sum(10) == 1080codegemma-7b. fail_base: True, fail_plus: True
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
assert square_Sum(2) == 10
"""
def square_sum(n):
return sum([i**2 for i in range(1, n*2, 2)])
code-llama-multi-13b. fail_base: True, fail_plus: True
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
assert square_Sum(2) == 10
"""
def square_Sum(n):
sum = 0
for i in range(1, n+1, 2):
sum += i**2
return sum
def square_Sum(n):
return sum([i**2 for i in range(1, n+1, 2)])
def square_Sum(n):
return sum(i**2 for i in range(1, n+1, 2))
def square_Sum(n):
return sum(i**2 for i in range(1, n+1) if i % 2 == 1)
def square_Sum(n):
return sum(i**2 for i in range(1, n+1) if i % 2)
def square_Sum(n):
return sum(i**2 for i in range(1, n+1) if i & 1)
def square_Sum(n):
return sum(i**2 for i in range(1, n+1) if i & 1 == 1)
def square_Sum(n):
return sum(i**2 for i in range(1, n+1) if i & 1 == 0)
def square_Sum(n):
return sum(i**2 for i in range(1, n+1) if i & 1 == 1)
def square_Sum(n):
return sum(i**2 for i in range(1, n+1) if i & 1 == 0)
def square_Sum(n):
return sum(i**2 for i in range(1, n+1) if i & 1)
def square_Sum(n):
return sum(i**2 for i in range(1, n+1) if i & 1 == 1)
def square_Sum(n):
return sum(i**2 for i in range(1, n+1) if i & 1 == 0)
def square_Sum(n):
return sum(i**2 for i in range(1, n+1) if i & 1)deepseek-coder-6.7b-instruct. fail_base: False, fail_plus: True
Here is the Python function in a markdown style code block:
```python
def square_Sum(n):
sum = 0
for i in range(1, 2*n, 2):
sum += i**2
return sum
# Test the function
assert square_Sum(2) == 10
```
In this function, we use a for loop to iterate over the first `n` odd numbers (from 1 to `2n-1`, with a step of 2). For each number `i`, we add its square (`i**2`) to the `sum`. Finally, we return the `sum`. The `assert` statement is used to test the function.
open-hermes-2.5-code-290k-13b. fail_base: True, fail_plus: True
def square_sum(n):
sum_of_squares = 0
for i in range(1, 2*n + 1, 2):
sum_of_squares += i**2
return sum_of_squares
assert square_sum(2) == 10codet5p-6b. fail_base: True, fail_plus: True
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
assert square_Sum(2) == 10
"""
def square_Sum(n):
sum = 0
for i in range(1, n+1, 2):
sum += i**2
return sum
print(square_Sum(2)) # 10
print(square_Sum(3)) # 30
print(square_Sum(4)) # 100
print(square_Sum(5)) # 285
print(square_Sum(6)) # 576
print(square_Sum(7)) # 801
print(square_Sum(8)) # 1600
print(square_Sum(9)) # 2025
print(square_Sum(10)) # 3240
print(square_Sum(11)) # 3655
print(square_Sum(12)) # 4900
print(square_Sum(13)) # 6405
print(square_Sum(14)) # 7896
print(square_Sum(15)) # 9295
print(square_Sum(16)) # 10800
print(square_Sum(17)) # 12555
print(square_Sum(18)) # 15450
print(square_Sum(19)) # 18225
print(square_Sum(20)) # 2025
print(square_Sum(21)) # 24550
print(square_Sum(22)) # 28625
print(square_Sum(23)) # 30900
print(square_Sum(24)) # 34275
print(square_Sum(25)) # 39600
print(square_Sum(26)) # 43825
print(square_Sum(27)) # 49575
print(square_Sum(28)) # 57600
print(square_Sum(29)) # 62925
print(square_Sum(30)) # 72950
print(square_Sum(31)) # 82975
print(square_Sum(32)) # 93600
print(square_Sum(33)) # 103525
print(square_Sum(34)) # 112650
print(square_Sum(35)) # 123625
print(square_Sum(36)) # 135650
print(square_Sum(37)) # 153675
print(square_Sum(38)) # 173700
print(square_Sum(39)) # 193755
print(square_Sum(40)) #codegemma-7b-it. fail_base: True, fail_plus: True
def square_Sum(n):
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
assert square_Sum(2) == 10
"""
sum = 0
for i in range(1, n+1):
sum += i**2
return summistralai--Mistral-7B-Instruct-v0.2. fail_base: True, fail_plus: True
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
assert square_Sum(2) == 10
"""
def square_sum(n):
"""
Returns the sum of the squares of the first n odd natural numbers.
"""
return sum(i**2 for i in range(1, n+1) if i % 2 != 0)
# Test case
assert square_sum(2) == 10xwincoder-34b. fail_base: False, fail_plus: True
def square_Sum(n):
sum = 0
for i in range(1, 2 * n, 2):
sum += i ** 2
return sum
assert square_Sum(2) == 10wizardcoder-15b. fail_base: False, fail_plus: True
Here's the Python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers:
```python
def square_Sum(n):
sum = 0
for i in range(1, n*2, 2):
sum += i**2
return sum
```
Explanation:
- We initialize a variable `sum` to 0.
- We use a `for` loop to iterate over the first `n` odd natural numbers. The `range` function starts at 1, increments by 2 (since we only want odd numbers), and stops at `n*2` (since we want `n` odd numbers).
- Inside the loop, we add the square of the current odd number to the `sum` variable.
- After the loop, we return the `sum` variable.
We can test the function with the following code:
```python
assert square_Sum(2) == 10
assert square_Sum(5) == 250
assert square_Sum(10) == 3025
```
These assertions should pass, since the function correctly calculates the sum of the squares of the first 2, 5, and 10 odd natural numbers.code-llama-34b. fail_base: False, fail_plus: True
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
assert square_Sum(2) == 10
"""
def square_Sum(n):
sum = 0
for i in range(1, 2*n + 1, 2):
sum += i**2
return sum
deepseek-coder-33b-instruct. fail_base: False, fail_plus: True
Here is the Python function implemented in a markdown style code block:
```python
def square_Sum(n):
sum = 0
for i in range(1, 2*n, 2):
sum += i**2
return sum
```
You can test the function with the following code:
```python
print(square_Sum(2)) # Output: 10
```
This function works by iterating over the first `n` odd natural numbers (which are `2*n` numbers apart by `2`) and adding the square of each number to the sum. The `range` function is used to generate the sequence of numbers, and the `**` operator is used to square each number.
phi-2. fail_base: False, fail_plus: True
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
assert square_Sum(2) == 10
"""
def square_Sum(n):
sum = 0
for i in range(1, 2*n, 2):
sum += i**2
return sum
assert square_Sum(2) == 10
codet5p-2b. fail_base: True, fail_plus: True
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
assert square_Sum(2) == 10
"""
def square_Sum(n):
sum = 0
for i in range(1,n+1):
if i%2!= 0:
sum += i**2
return sum
assert square_Sum(2) == 10
assert square_Sum(3) == 14
assert square_Sum(4) == 20
assert square_Sum(5) == 30
assert square_Sum(6) == 36
assert square_Sum(7) == 42
assert square_Sum(8) == 48
assert square_Sum(9) == 54
assert square_Sum(10) == 60
assert square_Sum(11) == 66
assert square_Sum(12) == 72
assert square_Sum(13) == 78
assert square_Sum(14) == 84
assert square_Sum(15) == 90
assert square_Sum(16) == 96
assert square_Sum(17) == 102
assert square_Sum(18) == 108
assert square_Sum(19) == 114
assert square_Sum(20) == 120
assert square_Sum(21) == 126
assert square_Sum(22) == 132
assert square_Sum(23) == 138
assert square_Sum(24) == 144
assert square_Sum(25) == 150
assert square_Sum(26) == 156
assert square_Sum(27) == 162
assert square_Sum(28) == 168
assert square_Sum(29) == 174
assert square_Sum(30) == 180
assert square_Sum(31) == 186
assert square_Sum(32) == 192
assert square_Sum(33) == 198
assert square_Sum(34) == 204
assert square_Sum(35) == 210
assert square_Sum(36) == 216
assert square_Sum(37) == 222
assert square_Sum(38) == 228
assert square_Sum(39) == 234
assert square_Sum(40) == 240
assert square_Sum(41) == 246
assert square_Sum(42) == 252
assert square_Sum(43) == 258
assert square_Sum(44) == 264
assert square_Sum(45) == 270
assert square_Sum(46) == 276
assert square_Sum(47) == 282
assert square_Sumbigcode--starcoder2-15b-instruct-v0.1. fail_base: False, fail_plus: True
def square_Sum(n):
sum = 0
for i in range(1, 2*n+1, 2):
sum += i*i
return sum
assert square_Sum(2) == 10
assert square_Sum(3) == 20
assert square_Sum(4) == 50
```codegemma-2b. fail_base: True, fail_plus: True
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
assert square_Sum(2) == 10
"""
def square_Sum(n):
sum = 0
for i in range(1, n+1):
if i % 2 != 0:
sum += i**2
return sum
white-rabbit-neo-33b-v1. fail_base: False, fail_plus: True
def square_Sum(n):
return sum(i**2 for i in range(1, 2*n, 2))
# Test the function
assert square_Sum(2) == 10microsoft--Phi-3-mini-4k-instruct. fail_base: True, fail_plus: True
def square_sum(n):
"""
Returns the sum of the squares of the first n odd natural numbers.
:param n: Number of odd natural numbers
:return: Sum of squares of the first n odd natural numbers
"""
sum_of_squares = 0
count = 0
# Iterate until count reaches n
while count < n:
num = 2 * count + 1 # Generate the next odd number
sum_of_squares += num ** 2
count += 1
return sum_of_squares
# Test the function
assert square_sum(2) == 10, f"Expected 10, but got {square_sum(2)}"
assert square_sum(3) == 35, f"Expected 35, but got {square_sum(3)}"
assert square_sum(4) == 194, f"Expected 194, but got {square_sum(4)}"
speechless-codellama-34b. fail_base: False, fail_plus: True
def square_Sum(n):
sum = 0
for i in range(1, 2*n+1, 2):
sum += i**2
return sum
# Test the function
assert square_Sum(2) == 10
```
meta-llama-3-70b-instruct. fail_base: False, fail_plus: True
def square_Sum(n):
return sum(i**2 for i in range(1, n*2 + 1, 2))
assert square_Sum(2) == 10stable-code-3b. fail_base: True, fail_plus: True
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
assert square_Sum(2) == 10
"""
def square_Sum(n):
return sum(i**2 for i in range(1, n+1, 2))
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n even natural numbers.
assert square_Sum(2) == 10
"""
def square_Sum(n):
return sum(i**2 for i in range(2, n+1, 2))
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
assert square_Sum(2) == 10
"""
def square_Sum(n):
return sum(i**2 for i in range(1, n+1, 2))
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n even natural numbers.
assert square_Sum(2) == 10
"""
def square_Sum(n):
return sum(i**2 for i in range(2, n+1, 2))
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
assert square_Sum(2) == 10
"""
def square_Sum(n):
return sum(i**2 for i in range(1, n+1, 2))
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n even natural numbers.
assert square_Sum(2) == 10
"""
def square_Sum(n):
return sum(i**2 for i in range(2, n+1, 2))
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
assert square_Sum(2) == 10
"""
def square_Sum(n):
return sum(i**2 for i in range(1, n+1, 2))
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n even natural numbers.
assert square_Sum(2) == 10
"""
def square_Sum(n):
return sum(i**codegen-6b. fail_base: True, fail_plus: True
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
assert square_Sum(2) == 10
"""
def square_Sum(n):
return sum([i**2 for i in range(1, n+1, 2)])
assert square_Sum(2) == 10
assert square_Sum(3) == 30
assert square_Sum(4) == 100
assert square_Sum(5) == 385
assert square_Sum(6) == 576
assert square_Sum(7) == 1225
assert square_Sum(8) == 3240
assert square_Sum(9) == 4891
assert square_Sum(10) == 8100
assert square_Sum(11) == 945
assert square_Sum(12) == 1680
assert square_Sum(13) == 2585
assert square_Sum(14) == 3450
assert square_Sum(15) == 4705
assert square_Sum(16) == 5776
assert square_Sum(17) == 7295
assert square_Sum(18) == 9090
assert square_Sum(19) == 10985
assert square_Sum(20) == 12240
assert square_Sum(21) == 14385
assert square_Sum(22) == 16705
assert square_Sum(23) == 18900
assert square_Sum(24) == 20985
assert square_Sum(25) == 22505
assert square_Sum(26) == 24750
assert square_Sum(27) == 26505
assert square_Sum(28) == 28750
assert square_Sum(29) == 30505
assert square_Sum(30) == 32505
assert square_Sum(31) == 34505
assert square_Sum(32) == 36505
assert square_Sum(33) == 38505
assert square_Sum(34) == 40505
assert square_Sum(35) == 42505
assert square_Sum(36) == 44505
assert square_Sum(37) == 46505
assert square_Sum(38) == 48505
assert square_Sum(39) == 50505
assert square_Sum(40) == 52505
assert square_Sum(41) == 54505
assert square_Sum(42) == 56505
assert square_Sum(43) == 58505
assert square_Sum(44) == 60505
assert square_Sum(45) == 62505gpt-4-1106-preview. fail_base: True, fail_plus: True
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
assert square_Sum(2) == 10
"""
def square_sum(n):
sum_of_squares = 0
odd_number = 1
for _ in range(n):
sum_of_squares += odd_number ** 2
odd_number += 2
return sum_of_squares
assert square_sum(2) == 10
gemma-7b-it. fail_base: True, fail_plus: True
def square_Sum(n):
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
assert square_Sum(2) == 10
"""
sum = 0
for i in range(1, n+1):
if i % 2 != 0:
sum += i**2
return sumopencodeinterpreter-ds-33b. fail_base: False, fail_plus: True
```python
def square_Sum(n):
sum = 0
for i in range(1, 2*n, 2):
sum += i**2
return sum
# Test the function
print(square_Sum(2)) # Output: 10openchat. fail_base: False, fail_plus: True
def square_Sum(n):
sum = 0
for i in range(1, 2*n, 2):
sum += i**2
return sum
assert square_Sum(2) == 10speechless-starcoder2-7b. fail_base: False, fail_plus: True
def square_Sum(n):
return sum(i**2 for i in range(1, n*2, 2))
assert square_Sum(2) == 10wizardcoder-7b. fail_base: False, fail_plus: True
Here's the Python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers:
```python
def square_Sum(n):
sum = 0
for i in range(1, n*2, 2):
sum += i**2
return sum
```
Explanation:
- We initialize a variable `sum` to 0 to keep track of the sum of squares of odd numbers.
- We use a `for` loop to iterate through the odd numbers from 1 to `n*2` (since the last odd number is `n*2-1`).
- For each odd number `i`, we add its square to the `sum` variable.
- Finally, we return the `sum` variable.
Example:
```python
>>> square_Sum(2)
10
```
This function will return 10 because the squares of the first two odd numbers are 1 and 9, which add up to 10. octocoder. fail_base: True, fail_plus: True
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
assert square_Sum(2) == 10
"""
def square_Sum(n):
sum = 0
for i in range(1, n+1, 2):
sum += i**2
return sum
gemma-1.1-7b-it. fail_base: True, fail_plus: True
def square_Sum(n):
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
assert squareSum(2) == 10
"""
sum = 0
for i in range(1, n + 1, 2):
sum += i**2
return sum
deepseek-coder-6.7b-base. fail_base: False, fail_plus: True
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
assert square_Sum(2) == 10
"""
def square_Sum(n):
sum = 0
for i in range(1, n*2, 2):
sum += i**2
return sum
print(square_Sum(2))codegen-16b. fail_base: True, fail_plus: True
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
assert square_Sum(2) == 10
"""
def square_Sum(n):
return sum([i**2 for i in range(1, n+1, 2)])
assert square_Sum(2) == 10
assert square_Sum(3) == 30
assert square_Sum(4) == 100
assert square_Sum(5) == 385
assert square_Sum(6) == 576
assert square_Sum(7) == 1225
assert square_Sum(8) == 3240
assert square_Sum(9) == 4891
assert square_Sum(10) == 8100
assert square_Sum(11) == 945
assert square_Sum(12) == 1680
assert square_Sum(13) == 2525
assert square_Sum(14) == 3270
assert square_Sum(15) == 4781
assert square_Sum(16) == 6400
assert square_Sum(17) == 7125
assert square_Sum(18) == 9300
assert square_Sum(19) == 10665
assert square_Sum(20) == 16800
assert square_Sum(21) == 22185
assert square_Sum(22) == 28625
assert square_Sum(23) == 34505
assert square_Sum(24) == 40440
assert square_Sum(25) == 49525
assert square_Sum(26) == 57600
assert square_Sum(27) == 64925
assert square_Sum(28) == 72950
assert square_Sum(29) == 82975
assert square_Sum(30) == 93600
assert square_Sum(31) == 104525
assert square_Sum(32) == 122400
assert square_Sum(33) == 142150
assert square_Sum(34) == 163500
assert square_Sum(35) == 184525
assert square_Sum(36) == 206400
assert square_Sum(37) == 226525
assert square_Sum(38) == 247450
assert square_Sum(39) == 269525
assert square_Sum(40) == 287600
assert square_Sum(41) == 309525
assert square_Sum(42) == 327675
assert square_Sum(43) == 346500
assert squaremistral-7b. fail_base: True, fail_plus: True
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
assert square_Sum(2) == 10
"""
def square_Sum(n):
sum = 0
for i in range(1, n+1, 2):
sum += i**2
return sum
assert square_Sum(2) == 10speechless-mistral-7b. fail_base: True, fail_plus: True
def square_Sum(n):
sum = 0
for i in range(1, n+1, 2):
sum += i**2
return sum
assert square_Sum(2) == 10
```
codet5p-16b. fail_base: True, fail_plus: True
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
assert square_Sum(2) == 10
"""
def square_Sum(n):
return sum([i**2 for i in range(1,n+1,2)])
assert square_Sum(2) == 10
assert square_Sum(3) == 25
assert square_Sum(4) == 30
assert square_Sum(5) == 55
assert square_Sum(6) == 70
assert square_Sum(7) == 85
assert square_Sum(8) == 100
assert square_Sum(9) == 125
assert square_Sum(10) == 150
assert square_Sum(11) == 175
assert square_Sum(12) == 200
assert square_Sum(13) == 225
assert square_Sum(14) == 250
assert square_Sum(15) == 275
assert square_Sum(16) == 300
assert square_Sum(17) == 325
assert square_Sum(18) == 350
assert square_Sum(19) == 375
assert square_Sum(20) == 400
assert square_Sum(21) == 425
assert square_Sum(22) == 450
assert square_Sum(23) == 475
assert square_Sum(24) == 500
assert square_Sum(25) == 525
assert square_Sum(26) == 550
assert square_Sum(27) == 575
assert square_Sum(28) == 600
assert square_Sum(29) == 625
assert square_Sum(30) == 650
assert square_Sum(31) == 675
assert square_Sum(32) == 700
assert square_Sum(33) == 725
assert square_Sum(34) == 750
assert square_Sum(35) == 775
assert square_Sum(36) == 800
assert square_Sum(37) == 825
assert square_Sum(38) == 850
assert square_Sum(39) == 875
assert square_Sum(40) == 900
assert square_Sum(41) == 925
assert square_Sum(42) == 950
assert square_Sum(43) == 975
assert square_Sum(44) == 1000
assert square_Sum(45) == 1025
assert square_Sum(46) == 1050
assert square_Sum(47) == 1075
assert square_Sum(48) == 1100
code-llama-13b. fail_base: True, fail_plus: True
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
assert square_Sum(2) == 10
"""
def square_Sum(n):
sum = 0
for i in range(1, n+1, 2):
sum += i**2
return sum
print(square_Sum(2))xdan-l1-chat. fail_base: True, fail_plus: True
def square_sum(n):
total = 0
for i in range(1, n+1, 2):
total += i**2
return total
assert square_sum(2) == 10solar-10.7b-instruct. fail_base: True, fail_plus: True
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
assert square_Sum(2) == 10
"""
def square_sum(n: int) -> int:
total_sum = 0
for num in range(1, n+1, 2):
total_sum += num ** 2
return total_sum
assert square_sum(2) == 10gemma-2b. fail_base: True, fail_plus: True
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
assert square_Sum(2) == 10
"""
def square_Sum(n):
sum = 0
for i in range(1, n+1):
sum += i**2
return sum
claude-3-sonnet-20240229. fail_base: False, fail_plus: True
Here's the Python function to solve the problem, wrapped in a markdown block:
```python
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
assert square_Sum(2) == 10
"""
def square_Sum(n):
"""
Returns the sum of the squares of the first n odd natural numbers.
Args:
n (int): The number of odd natural numbers to consider.
Returns:
int: The sum of the squares of the first n odd natural numbers.
"""
total = 0
for i in range(1, 2*n, 2):
total += i**2
return totalstarcoder2-15b-oci. fail_base: False, fail_plus: True
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
assert square_Sum(2) == 10
"""
def square_Sum(n):
sum = 0
for i in range(1, n*2, 2):
sum += i**2
return sum
starcoder2-3b. fail_base: True, fail_plus: True
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
assert square_Sum(2) == 10
"""
def square_Sum(n):
sum = 0
for i in range(1, n+1):
sum += i**2
return sum
print(square_Sum(2))
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
assert square_Sum(2) == 10
"""
def square_Sum(n):
sum = 0
for i in range(1, n+1):
sum += i**2
return sum
print(square_Sum(2))
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
assert square_Sum(2) == 10
"""
def square_Sum(n):
sum = 0
for i in range(1, n+1):
sum += i**2
return sum
print(square_Sum(2))
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
assert square_Sum(2) == 10
"""
def square_Sum(n):
sum = 0
for i in range(1, n+1):
sum += i**2
return sum
print(square_Sum(2))
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
assert square_Sum(2) == 10
"""
def square_Sum(n):
sum = 0
for i in range(1, n+1):
sum += i**2
return sum
print(square_Sum(2))
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
assert square_Sum(2) == 10
"""
def square_Sum(n):
sum = 0
for i in range(1, n+1):
sum += i**2
return sum
print(square_Sum(2))
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbersspeechless-starcoder2-15b. fail_base: False, fail_plus: True
def square_Sum(n):
sum = 0
for i in range(1, 2*n, 2):
sum += i**2
return sum
assert square_Sum(2) == 10gemma-7b. fail_base: True, fail_plus: True
"""
Write a python function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.
assert square_Sum(2) == 10
"""
def square_sum(n):
sum = 0
for i in range(1, n + 1):
sum += i * i
return sum
opencodeinterpreter-ds-6.7b. fail_base: False, fail_plus: True
```python
def square_Sum(n):
sum = 0
num = 1
for i in range(n):
sum += num*num
num += 2
return sum
# Test the function
print(square_Sum(2))
```