Mbpp/558

 """
Write a python function to find the sum of the per-digit difference between two integers.
assert digit_distance_nums(1,2) == 1
"""
 

solution

 
def digit_distance_nums(n1, n2):
    return sum([abs(int(c1) - int(c2)) for c1, c2 in zip(str(n1), str(n2))])
 

base input

 [[1, 2], [23, 56], [123, 256]] 

plus input

 [[123456789, 987654321], [12345, 9], [9876543210, 123], [11111111, 99999999], [123456789, 987654321], [98765, 54321], [999999, 111111], [0, 987654321], [987654321, 23456789], [123456789123456789, 987654321987654321], [1000000, 999999], [9999, 8888], [123456789, 123], [1, 1234567890], [12345, 567891], [0, 256], [123, 0], [0, 0], [1000000, 999999], [123, 456789], [12345, 5678], [1111, 2222], [1020304, 2030405], [1, 9], [10000000, 9999999], [200, 500], [3000, 30], [10, 256], [123, 5], [10, 10], [9999999999, 1111111111], [123, 256789], [23, 568], [0, 0], [0, 1], [1, 0], [1, 1], [3, 0], [24, 30], [9876543, 12], [1, 2], [23, 56], [123, 256], [8888, 9999], [5678, 1000000], [256, 256], [9999, 0], [123, 122], [30, 2], [123456788, 123456789], [1234567888, 1234567889], [1000000, 256], [12, 256], [256, 456789], [11, 256], [99999999, 99999999], [1234567889, 568], [1, 5], [23456788, 23456789], [123, 123], [54321, 0], [56, 9876543], [500, 500], [10000000, 10000000], [23456787, 23456789], [999999, 456789], [10001, 10000], [1111, 2223], [5, 568], [98765, 98765], [1111111111, 1111111111], [201, 500], [201, 123456788], [3, 2223], [456788, 456788], [23456788, 11111111], [567890, 567891], [54321, 123], [123456789, 123456789], [999999, 0], [2, 1], [10000, 123456788], [8889, 8888], [10, 8888], [1, 1111111111], [1111111111, 1111111110], [456787, 123], [98766, 54321], [256789, 1000000], [456789, 456789], [202, 201], [123456789123456789, 1234567890], [23456787, 23456788], [1111111110, 1111111110], [5678, 987654321987654320], [11111111, 123456789], [1000001, 256], [1111111112, 1], [1, 123], [456788, 123456789123456789], [2, 2], [1234567889, 202], [9, 56], [11, 11], [3, 2], [567, 568], [567890, 567890], [256, 3], [257, 257], [10, 499], [9, 256], [1000000, 1000000], [123456789, 123456790], [99999999, 3000], [98765, 987654321], [568, 8888], [0, 11111111], [8889, 8889], [1000003, 1000001], [456788, 456789], [1111111111, 9], [1111111111, 11], [5678, 9999], [8889, 56], [12346, 9], [9999, 2], [999998, 999999], [6, 5], [201, 200], [98765, 568], [8888, 8888], [99999999, 456789], [9999999999, 9999999999], [1000001, 1000001], [255, 256], [23456788, 8888], [123456788, 256], [501, 456789], [255, 1000001], [5678, 12], [1111111111, 2224], [987654321, 987654321], [9, 2030405]] 

Generations

code-llama-multi-7b. fail_base: False, fail_plus: True

  """
Write a python function to find the sum of the per-digit difference between two integers.
assert digit_distance_nums(1,2) == 1
"""


def digit_distance_nums(num1, num2):
    """
    :param num1: int
    :param num2: int
    :return: int
    """
    num1_list = list(str(num1))
    num2_list = list(str(num2))
    if len(num1_list) != len(num2_list):
        return 0
    else:
        return sum([abs(int(num1_list[i]) - int(num2_list[i])) for i in range(len(num1_list))])


if __name__ == '__main__':
    print(digit_distance_nums(1, 2))
    print(digit_distance_nums(12, 23))
    print(digit_distance_nums(123, 234))
    print(digit_distance_nums(1234, 2345))
    print(digit_distance_nums(12345, 23456))
    print(digit_distance_nums(123456, 234567))
    print(digit_distance_nums(1234567, 2345678))
    print(digit_distance_nums(12345678, 23456789))
    print(digit_distance_nums(123456789, 234567890))
    print(digit_distance_nums(1234567890, 2345678901))
    print(digit_distance_nums(12345678901, 23456789012))
    print(digit_distance_nums(123456789012, 23456789013))
    print(digit_distance_nums(1234567890123, 234567890124

databricks--dbrx-instruct. fail_base: False, fail_plus: True

  def digit_distance_nums(num1, num2):
    """
    This function calculates the sum of the per-digit difference between two integers.
    """
    # Convert numbers to absolute value to handle negative inputs
    num1, num2 = abs(num1), abs(num2)
    # Initialize the result variable
    result = 0
    # Loop through the digits of the numbers
    while num1 > 0 or num2 > 0:
        # Calculate the difference between the current digits
        digit_diff = (num1 % 10) - (num2 % 10)
        # Add the absolute value of the difference to the result
        result += abs(digit_diff)
        # Remove the current digits from the numbers
        num1 //= 10
        num2 //= 10
    return result

# Test the function
assert digit_distance_nums(1, 2) == 1
assert digit_distance_nums(123, 456) == 9
assert digit_distance_nums(-789, 321) == 20

CohereForAI--c4ai-command-r-plus. fail_base: False, fail_plus: True

  def digit_distance_nums(num1: int, num2: int) -> int:
    """
    Calculate the sum of the per-digit difference between two integers.

    Parameters:
    - num1 (int): The first integer.
    - num2 (int): The second integer.

    Returns:
    - int: The sum of the per-digit differences.
    """
    str_num1 = str(num1)
    str_num2 = str(num2)

    max_length = max(len(str_num1), len(str_num2))

    padded_num1 = str_num1.zfill(max_length)
    padded_num2 = str_num2.zfill(max_length)

    return sum(abs(int(digit1) - int(digit2)) for digit1, digit2 in zip(padded_num1, padded_num2))
```

claude-3-haiku-20240307. fail_base: False, fail_plus: True

  Here's the solution wrapped in a Python markdown block:

```python
def digit_distance_nums(num1, num2):
    """
    Find the sum of the per-digit difference between two integers.
    
    Args:
        num1 (int): The first integer.
        num2 (int): The second integer.
    
    Returns:
        int: The sum of the per-digit difference between the two integers.
    """
    num1_str = str(num1)
    num2_str = str(num2)
    
    # Ensure both numbers have the same number of digits
    max_len = max(len(num1_str), len(num2_str))
    num1_str = num1_str.zfill(max_len)
    num2_str = num2_str.zfill(max_len)
    
    total_diff = 0
    for i in range(max_len):
        total_diff += abs(int(num1_str[i]) - int(num2_str[i]))
    
    return total_diff

# Test the function
assert digit_distance_nums(1, 2) == 1

code-millenials-34b. fail_base: False, fail_plus: True

  def digit_distance_nums(num1, num2):
    # convert numbers to strings to be able to iterate over digits
    str_num1 = str(num1)
    str_num2 = str(num2)

    # get the length of the longer string
    max_len = max(len(str_num1), len(str_num2))

    # initialize sum variable
    total_sum = 0

    # iterate over each index in the range of max_len
    for i in range(max_len):
        # get the digit at the current index for each number
        digit_num1 = int(str_num1[i]) if i < len(str_num1) else 0
        digit_num2 = int(str_num2[i]) if i < len(str_num2) else 0

        # add the absolute difference between the digits to the total sum
        total_sum += abs(digit_num1 - digit_num2)

    return total_sum

# test the function
assert digit_distance_nums(1,2) == 1

dolphin-2.6. fail_base: False, fail_plus: True

  """
Write a python function to find the sum of the per-digit difference between two integers.
assert digit_distance_nums(1,2) == 1
"""
def digit_distance_nums(num1, num2):
    # Convert the numbers to strings to iterate over the digits
    num1_str = str(num1)
    num2_str = str(num2)

    # Calculate the absolute difference between the corresponding digits
    diff_list = [abs(int(num1_str[i]) - int(num2_str[i])) for i in range(len(num1_str))]

    # Return the sum of the differences
    return sum(diff_list)

claude-3-opus-20240229. fail_base: False, fail_plus: True

  Here's the Python code to solve the problem, wrapped in a Python markdown block:

```python
def digit_distance_nums(num1, num2):
    # Convert the numbers to strings
    str_num1 = str(num1)
    str_num2 = str(num2)
    
    # Pad the shorter string with leading zeros if necessary
    max_length = max(len(str_num1), len(str_num2))
    str_num1 = str_num1.zfill(max_length)
    str_num2 = str_num2.zfill(max_length)
    
    # Calculate the per-digit difference and sum them up
    total_difference = 0
    for digit1, digit2 in zip(str_num1, str_num2):
        difference = abs(int(digit1) - int(digit2))
        total_difference += difference
    
    return total_difference

# Test the function
assert digit_distance_nums(1, 2) == 1
assert digit_distance_nums(123, 321) == 4
assert digit_distance_nums(1234, 5678) == 16

mixtral-8x7b-instruct. fail_base: False, fail_plus: True

  def digit_distance_nums(num1, num2):
    """
    This function calculates the sum of the per-digit difference between two integers.
    :param num1: int, the first integer
    :param num2: int, the second integer
    :return: int, the sum of the per-digit difference
    """
    # Convert the integers to strings for easier manipulation
    num1_str = str(num1)
    num2_str = str(num2)

    # Determine the length of the longer number
    max_length = max(len(num1_str), len(num2_str))

    # Pad the shorter number with zeros to ensure both numbers have the same length
    num1_padded = num1_str.zfill(max_length)
    num2_padded = num2_str.zfill(max_length)

    # Initialize the sum of per-digit differences
    sum_diff = 0

    # Iterate through the digits of the padded numbers
    for i in range(max_length):
        # Calculate the absolute difference between the digits
        diff = abs(int(num1_padded[i]) - int(num2_padded[i]))
        # Add the difference to the sum
        sum_diff += diff

    return sum_diff

# Test the function
assert digit_distance_nums(1, 2) == 1

wizardcoder-34b. fail_base: True, fail_plus: True

  Here's the Python function to find the sum of the per-digit difference between two integers:

```python
def digit_distance_nums(num1, num2):
    """
    This function takes two integers as input and returns the sum of the per-digit difference between them.
    """
    # Convert the integers to strings to access each digit
    num1_str = str(num1)
    num2_str = str(num2)
    
    # Initialize a variable to store the sum of the per-digit difference
    diff_sum = 0
    
    # Loop through each digit of the longer number and subtract the corresponding digit of the shorter number
    # If the shorter number has less digits, pad it with zeros on the left
    for i in range(max(len(num1_str), len(num2_str)):
        diff = int(num1_str[i]) - int(num2_str[i]) if i < len(num1_str) else int(num1_str[-1]) - int(num2_str[i-len(num1_str)])
        diff_sum += abs(diff)
    
    return diff_sum
```

We can test the function using the given example:

```python
assert digit_distance_nums(1,2) == 1
```

This should return `True` since the per-digit difference between 1 and 2 is 1. 

mixtral-8x22b-instruct-v0.1. fail_base: False, fail_plus: True

  def digit_distance_nums(num1, num2):
    # Convert the numbers to strings to easily access individual digits
    str1 = str(num1)
    str2 = str(num2)

    # Calculate the length of the longer number
    length = max(len(str1), len(str2))

    # Pad the shorter number with zeros to match the length of the longer number
    str1 = str1.zfill(length)
    str2 = str2.zfill(length)

    # Calculate the sum of the per-digit difference between the two numbers
    return sum(abs(int(a) - int(b)) for a, b in zip(str1, str2))

# Test the function
assert digit_distance_nums(1, 2) == 1
assert digit_distance_nums(123, 456) == 9
assert digit_distance_nums(100, 200) == 100
assert digit_distance_nums(999, 1) == 27

code-llama-multi-34b. fail_base: False, fail_plus: True

  """
Write a python function to find the sum of the per-digit difference between two integers.
assert digit_distance_nums(1,2) == 1
"""


def digit_distance_nums(num1, num2):
    """
    :param num1: int
    :param num2: int
    :return: int
    """
    num1_list = [int(i) for i in str(num1)]
    num2_list = [int(i) for i in str(num2)]
    return sum([abs(num1_list[i] - num2_list[i]) for i in range(len(num1_list))])


if __name__ == '__main__':
    print(digit_distance_nums(1, 2))

Qwen--Qwen1.5-72B-Chat. fail_base: False, fail_plus: True

  def digit_distance_nums(num1, num2):
    # Convert numbers to strings to iterate over their digits
    str_num1 = str(abs(num1))
    str_num2 = str(abs(num2))
    
    # Make sure both numbers have the same number of digits
    max_len = max(len(str_num1), len(str_num2))
    str_num1 = str_num1.zfill(max_len)
    str_num2 = str_num2.zfill(max_len)
    
    # Calculate the per-digit difference and sum them up
    diff_sum = sum(abs(int(digit1) - int(digit2)) for digit1, digit2 in zip(str_num1, str_num2))
    
    # If the original numbers have different signs, add the absolute value of their difference
    if (num1 < 0) != (num2 < 0):
        diff_sum += abs(num1 - num2)
    
    return diff_sum

# Test cases
assert digit_distance_nums(1, 2) == 1
assert digit_distance_nums(-10, 20) == 20
assert digit_distance_nums(123, 456) == 10
assert digit_distance_nums(-987, 654) == 231

mistral-large-latest. fail_base: False, fail_plus: True

  Sure, here is a Python function that calculates the sum of the per-digit difference between two integers:

```python
def digit_distance_nums(num1, num2):
    str_num1 = str(num1)
    str_num2 = str(num2)
    distance = 0

    # Pad the shorter string with leading zeros
    if len(str_num1) > len(str_num2):
        str_num2 = str_num2.zfill(len(str_num1))
    else:
        str_num1 = str_num1.zfill(len(str_num2))

    # Calculate the per-digit difference and sum them up
    for i in range(len(str_num1)):
        distance += abs(int(str_num1[i]) - int(str_num2[i]))

    return distance

# Test the function
assert digit_distance_nums(1, 2) == 1
```

This function first converts the integers to strings and pads the shorter string with leading zeros if necessary. Then it calculates the absolute difference of each pair of corresponding digits and sums them up.

codegen-2b. fail_base: True, fail_plus: True

  """
Write a python function to find the sum of the per-digit difference between two integers.
assert digit_distance_nums(1,2) == 1
"""

def digit_distance_nums(num1, num2):
    """
    :type num1: int
    :type num2: int
    :rtype: int
    """
    # num1 = int(str(num1)[::-1])
    # num2 = int(str(num2)[::-1])
    # print(num1, num2)
    # print(num1, num2)
    # print(num1, num2)
    # print(num1, num2)
    # print(num1, num2)
    # print(num1, num2)
    # print(num1, num2)
    # print(num1, num2)
    # print(num1, num2)
    # print(num1, num2)
    # print(num1, num2)
    # print(num1, num2)
    # print(num1, num2)
    # print(num1, num2)
    # print(num1, num2)
    # print(num1, num2)
    # print(num1, num2)
    # print(num1, num2)
    # print(num1, num2)
    # print(num1, num2)
    # print(num1, num2)
    # print(num1, num2)
    # print(num1, num2)
    # print(num1, num2)
    # print(num1, num2)
    # print(num1, num2)
    # print(num1, num2)
    # print(num1, num2)
    # print(num1, num2)
    # print(num1, num2)
    # print(num1, num2)
    # print(num1, num2)
    # print(num1, num2)
    # print(num1, num2)
    # print(num1, num2)
    # print(num1, num2)
    # print(num1, num2)
    # print(num1, num2)
    # print(num1, num2)
    # print(

HuggingFaceH4--starchat2-15b-v0.1. fail_base: False, fail_plus: True

  def digit_distance_nums(num1, num2):
    """
    Write a python function to find the sum of the per-digit difference between two integers.
    assert digit_distance_nums(1,2) == 1
    """
    # Convert integers to strings for easy digit extraction
    str_num1 = str(num1)
    str_num2 = str(num2)

    # Make sure both numbers have the same length by padding with zeros
    if len(str_num1) < len(str_num2):
        str_num1 = str_num1.zfill(len(str_num2))
    elif len(str_num1) > len(str_num2):
        str_num2 = str_num2.zfill(len(str_num1))

    # Calculate the sum of the per-digit differences
    distance_sum = sum(abs(int(digit1) - int(digit2)) for digit1, digit2 in zip(str_num1, str_num2))

    return distance_sum

# Test the function
assert digit_distance_nums(1,2) == 1
assert digit_distance_nums(123, 456) == 9
assert digit_distance_nums(12345, 67890) == 15
assert digit_distance_nums(0, 0) == 0
assert digit_distance_nums(100, 200) == 2

codegemma-7b. fail_base: False, fail_plus: True

  """
Write a python function to find the sum of the per-digit difference between two integers.
assert digit_distance_nums(1,2) == 1
"""

def digit_distance_nums(num1, num2):
    """
    >>> digit_distance_nums(1,2)
    1
    >>> digit_distance_nums(10,20)
    10
    >>> digit_distance_nums(10,200)
    110
    """
    num1 = str(num1)
    num2 = str(num2)
    if len(num1) < len(num2):
        num1 = num1.zfill(len(num2))
    elif len(num1) > len(num2):
        num2 = num2.zfill(len(num1))
    return sum([abs(int(num1[i]) - int(num2[i])) for i in range(len(num1))])

code-llama-multi-13b. fail_base: True, fail_plus: True

  """
Write a python function to find the sum of the per-digit difference between two integers.
assert digit_distance_nums(1,2) == 1
"""

def digit_distance_nums(num1, num2):
    """
    :param num1: int
    :param num2: int
    :return: int
    """
    num1_str = str(num1)
    num2_str = str(num2)
    num1_list = list(num1_str)
    num2_list = list(num2_str)
    num1_list.sort()
    num2_list.sort()
    num1_str = ''.join(num1_list)
    num2_str = ''.join(num2_list)
    num1 = int(num1_str)
    num2 = int(num2_str)
    return abs(num1 - num2)


if __name__ == '__main__':
    print(digit_distance_nums(1, 2))
    print(digit_distance_nums(123, 456))
    print(digit_distance_nums(123, 321))
    print(digit_distance_nums(123, 123))
    print(digit_distance_nums(123, 1234))
    print(digit_distance_nums(1234, 123))
    print(digit_distance_nums(1234, 1234))
    print(digit_distance_nums(1234, 1235))
    print(digit_distance_nums(1234, 1236))
    print(digit_distance_nums(1234, 1237))
    print(digit_distance_nums(1234, 1238))
    print(digit_distance_nums(1234, 1239))
    print(digit_distance_nums(1234, 1230))
    print(digit_distance_nums(1234, 1229))
    print(digit_distance_nums(1234, 1228))
    print

deepseek-coder-6.7b-instruct. fail_base: False, fail_plus: True

  Here is the Python function in a markdown style code block:

```python
def digit_distance_nums(num1, num2):
    # Convert the numbers to strings
    str_num1 = str(num1)
    str_num2 = str(num2)

    # Find the length of the numbers
    len_num1 = len(str_num1)
    len_num2 = len(str_num2)

    # Initialize the sum of the per-digit difference
    sum_diff = 0

    # Loop through each digit in the numbers
    for i in range(max(len_num1, len_num2)):
        # If the digit exists in both numbers, add the difference to the sum
        if i < len_num1 and i < len_num2:
            sum_diff += abs(int(str_num1[i]) - int(str_num2[i]))
        # If the digit only exists in the first number, add the digit to the sum
        elif i < len_num1:
            sum_diff += int(str_num1[i])
        # If the digit only exists in the second number, add the digit to the sum
        else:
            sum_diff += int(str_num2[i])

    return sum_diff

# Test the function
assert digit_distance_nums(1,2) == 1
```

This function works by first converting the input numbers to strings. It then finds the length of these strings, which represents the number of digits in the numbers. It initializes a variable to keep track of the sum of the per-digit differences. It then loops through each digit in the numbers. If the digit exists in both numbers, it adds the difference to the sum. If the digit only exists in one number, it adds the digit to the sum. Finally, it returns the sum of the per-digit differences.

open-hermes-2.5-code-290k-13b. fail_base: True, fail_plus: True

  
def digit_distance_nums(num1, num2):
    # Convert the numbers to strings
    str1 = str(num1)
    str2 = str(num2)

    # Initialize the sum variable
    sum_diff = 0

    # Iterate through each digit in the first number
    for digit1 in str1:
        # Convert the digit back to an integer
        digit1 = int(digit1)

        # Iterate through each digit in the second number
        for digit2 in str2:
            # Convert the digit back to an integer
            digit2 = int(digit2)

            # Calculate the difference between the digits
            diff = abs(digit1 - digit2)

            # Add the difference to the sum
            sum_diff += diff

    return sum_diff

# Test the function with the given example
assert digit_distance_nums(1, 2) == 1

codet5p-6b. fail_base: False, fail_plus: True

  """
Write a python function to find the sum of the per-digit difference between two integers.
assert digit_distance_nums(1,2) == 1
"""


def digit_distance_nums(num1, num2):
    num1_digits = [int(x) for x in str(num1)]
    num2_digits = [int(x) for x in str(num2)]
    return sum([abs(num1_digits[i] - num2_digits[i]) for i in range(len(num1_digits))])

assert digit_distance_nums(1,2) == 1
assert digit_distance_nums(1,3) == 2
assert digit_distance_nums(1,4) == 3
assert digit_distance_nums(1,5) == 4
assert digit_distance_nums(1,6) == 5
assert digit_distance_nums(1,7) == 6
assert digit_distance_nums(1,8) == 7
assert digit_distance_nums(1,9) == 8
assert digit_distance_nums(1,10) == 9
assert digit_distance_nums(1,11) == 10
assert digit_distance_nums(1,12) == 11
assert digit_distance_nums(1,13) == 12
assert digit_distance_nums(1,14) == 13
assert digit_distance_nums(1,15) == 14
assert digit_distance_nums(1,16) == 15
assert digit_distance_nums(1,17) == 16
assert digit_distance_nums(1,18) == 17
assert digit_distance_nums(1,19) == 18
assert digit_distance_nums(1,20) == 19
assert digit_distance_nums(1,21) == 20
assert digit_distance_nums(1,22) == 21
assert digit_distance_nums(1,23) == 22
assert digit_distance_nums(1,24) == 23
assert digit_distance_nums(1,25) == 24
assert digit_distance_nums(1,26) == 25
assert digit_distance_nums(1,27) == 26
assert digit_distance_nums(1,28) == 27
assert digit_distance_nums(1,

codegemma-7b-it. fail_base: False, fail_plus: True

  def digit_distance_nums(num1, num2):
  """
  Write a python function to find the sum of the per-digit difference between two integers.
  assert digit_distance_nums(1,2) == 1
  """
  str1 = str(num1)
  str2 = str(num2)
  sum_diff = 0
  for i in range(max(len(str1), len(str2))):
    digit1 = int(str1[i]) if i < len(str1) else 0
    digit2 = int(str2[i]) if i < len(str2) else 0
    sum_diff += abs(digit1 - digit2)
  return sum_diff

mistralai--Mistral-7B-Instruct-v0.2. fail_base: True, fail_plus: True

  """
Write a python function to find the sum of the per-digit difference between two integers.
assert digit_distance_nums(1,2) == 1
"""
def digit_distance_nums(num1, num2):
    """
    Calculates the sum of the per-digit difference between two integers.

    :param num1: The first integer
    :param num2: The second integer
    :return: The sum of the per-digit differences
    """
    # Convert integers to strings for easier digit access
    str_num1 = str(num1)
    str_num2 = str(num2)

    # Calculate per-digit differences and sum them up
    result = 0
    for i in range(len(max(str_num1, str_num2))):
        digit_diff = ord(str_num1[i if len(str_num1) > i else '0') - ord('0') \
                       if i < len(str_num1) \
                       else ord(str_num2[i]) - ord('0')
        result += digit_diff

    return result

# Test the function
assert digit_distance_nums(1, 2) == 1

xwincoder-34b. fail_base: False, fail_plus: True

  def digit_distance_nums(a, b):
    num_str_a = str(a)
    num_str_b = str(b)
    max_len = max(len(num_str_a), len(num_str_b))
    
    num_str_a = num_str_a.zfill(max_len)
    num_str_b = num_str_b.zfill(max_len)
    
    distance = 0
    for i in range(max_len):
        distance += abs(int(num_str_a[i]) - int(num_str_b[i]))
    
    return distance

assert digit_distance_nums(1, 2) == 1

wizardcoder-15b. fail_base: False, fail_plus: False

  Here's the Python function to find the sum of the per-digit difference between two integers:

```python
def digit_distance_nums(num1, num2):
    # Convert the integers to strings and extract their digits
    digits1 = [int(d) for d in str(num1)]
    digits2 = [int(d) for d in str(num2)]
    
    # Calculate the per-digit difference and sum them up
    diff_sum = sum([abs(d1 - d2) for d1, d2 in zip(digits1, digits2)])
    
    return diff_sum
```

The function takes two integers as input and first converts them to strings and extracts their digits. It then calculates the per-digit difference between the two integers using a list comprehension and the `zip()` function. Finally, it sums up the absolute differences and returns the result.

To test the function, we can use the `assert` statement:

```python
assert digit_distance_nums(1,2) == 1
```

This will raise an `AssertionError` if the function returns a different value than 1.

code-llama-34b. fail_base: False, fail_plus: True

  """
Write a python function to find the sum of the per-digit difference between two integers.
assert digit_distance_nums(1,2) == 1
"""

def digit_distance_nums(num1, num2):
    num1_str = str(num1)
    num2_str = str(num2)
    num1_list = []
    num2_list = []
    for i in num1_str:
        num1_list.append(int(i))
    for i in num2_str:
        num2_list.append(int(i))
    if len(num1_list) > len(num2_list):
        num2_list += [0] * (len(num1_list) - len(num2_list))
    elif len(num1_list) < len(num2_list):
        num1_list += [0] * (len(num2_list) - len(num1_list))
    else:
        pass
    return sum([abs(num1_list[i] - num2_list[i]) for i in range(len(num1_list))])






















































































































































































































































































deepseek-coder-33b-instruct. fail_base: False, fail_plus: True

  Here is the Python function to find the sum of the per-digit difference between two integers:

```python
def digit_distance_nums(num1, num2):
    # Convert the numbers to strings
    str_num1 = str(num1)
    str_num2 = str(num2)

    # Make both strings the same length by adding leading zeros
    max_len = max(len(str_num1), len(str_num2))
    str_num1 = str_num1.zfill(max_len)
    str_num2 = str_num2.zfill(max_len)

    # Calculate the sum of the per-digit difference
    sum_difference = 0
    for i in range(max_len):
        sum_difference += abs(int(str_num1[i]) - int(str_num2[i]))

    return sum_difference
```

You can test the function with the provided assertion:

```python
assert digit_distance_nums(1,2) == 1
```

This function works by first converting the input numbers to strings. It then makes both strings the same length by adding leading zeros if necessary. After that, it calculates the sum of the per-digit difference by iterating over the digits of the two numbers and adding the absolute difference of the corresponding digits to the sum.

phi-2. fail_base: False, fail_plus: False

  """
Write a python function to find the sum of the per-digit difference between two integers.
assert digit_distance_nums(1,2) == 1
"""

def digit_distance_nums(a,b):
    """
    a,b: two integers
    return: the sum of the per-digit difference between a and b
    """
    return sum(abs(int(x)-int(y)) for x,y in zip(str(a),str(b)))

assert digit_distance_nums(1,2) == 1
assert digit_distance_nums(12,21) == 3
assert digit_distance_nums(123,321) == 0
assert digit_distance_nums(123,12) == 3
assert digit_distance_nums(123,321) == 0
assert digit_distance_nums(123,1234) == 3
assert digit_distance_nums(123,1234) == 3
assert digit_distance_nums(123,1234) == 3
assert digit_distance_nums(123,1234) == 3
assert digit_distance_nums(123,1234) == 3
assert digit_distance_nums(123,1234) == 3
assert digit_distance_nums(123,1234) == 3
assert digit_distance_nums(123,1234) == 3
assert digit_distance_nums(123,1234) == 3
assert digit_distance_nums(123,1234) == 3
assert digit_distance_nums(123,1234) == 3
assert digit_distance_nums(123,1234) == 3
assert digit_distance_nums(123,1234) == 3
assert digit_distance_nums(123,1234) == 3
assert digit_distance_nums(123,1234) == 3
assert digit_distance_nums(123,1234) == 3
assert digit_distance_nums(123,1234) == 3
assert digit_distance_nums(123,1234) == 3
assert digit_distance_nums(123,1234) == 3
assert digit_distance_nums(123,1234) == 3
assert digit_distance_nums(123,1234) == 3
assert digit_distance_nums(123,1234) == 3
assert digit_distance_nums(123,

codet5p-2b. fail_base: True, fail_plus: True

  """
Write a python function to find the sum of the per-digit difference between two integers.
assert digit_distance_nums(1,2) == 1
"""

def digit_distance_nums(num1, num2):
    diff = abs(num1 - num2)
    return sum(map(lambda x: x**2, diff))

assert digit_distance_nums(1,2) == 1
assert digit_distance_nums(1,3) == 2
assert digit_distance_nums(1,4) == 3
assert digit_distance_nums(1,5) == 4
assert digit_distance_nums(1,6) == 5
assert digit_distance_nums(1,7) == 6
assert digit_distance_nums(1,8) == 7
assert digit_distance_nums(1,9) == 8
assert digit_distance_nums(1,10) == 9
assert digit_distance_nums(1,11) == 10
assert digit_distance_nums(1,12) == 11
assert digit_distance_nums(1,13) == 12
assert digit_distance_nums(1,14) == 13
assert digit_distance_nums(1,15) == 14
assert digit_distance_nums(1,16) == 15
assert digit_distance_nums(1,17) == 16
assert digit_distance_nums(1,18) == 17
assert digit_distance_nums(1,19) == 18
assert digit_distance_nums(1,20) == 19
assert digit_distance_nums(1,21) == 20
assert digit_distance_nums(1,22) == 21
assert digit_distance_nums(1,23) == 22
assert digit_distance_nums(1,24) == 23
assert digit_distance_nums(1,25) == 24
assert digit_distance_nums(1,26) == 25
assert digit_distance_nums(1,27) == 26
assert digit_distance_nums(1,28) == 27
assert digit_distance_nums(1,29) == 28
assert digit_distance_nums(1,30) == 29
assert digit_distance_nums(1,31) == 30
assert digit_distance_nums(1,32) == 31
assert digit_

bigcode--starcoder2-15b-instruct-v0.1. fail_base: False, fail_plus: True

  def digit_distance_nums(num1, num2):
    num1_str = str(num1)
    num2_str = str(num2)
    max_len = max(len(num1_str), len(num2_str))
    num1_str = num1_str.rjust(max_len, '0')
    num2_str = num2_str.rjust(max_len, '0')
    diff_sum = 0
    for i in range(max_len):
        diff_sum += abs(int(num1_str[i]) - int(num2_str[i]))
    return diff_sum

codegemma-2b. fail_base: True, fail_plus: True

  """
Write a python function to find the sum of the per-digit difference between two integers.
assert digit_distance_nums(1,2) == 1
"""

def digit_distance_nums(num1, num2):
    sum = 0
    for i in str(num1):
        sum += int(i)
    for i in str(num2):
        sum -= int(i)
    return sum
<|file_separator|>

white-rabbit-neo-33b-v1. fail_base: False, fail_plus: True

  def digit_distance_nums(num1, num2):
    # Convert the numbers to strings to iterate over each digit
    str_num1 = str(num1)
    str_num2 = str(num2)
    
    # Pad the shorter number with zeros to match the length of the longer number
    if len(str_num1) < len(str_num2):
        str_num1 = str_num1.zfill(len(str_num2))
    else:
        str_num2 = str_num2.zfill(len(str_num1))
    
    # Calculate the sum of the per-digit difference
    sum_of_differences = sum(abs(int(digit1) - int(digit2)) for digit1, digit2 in zip(str_num1, str_num2))
    
    return sum_of_differences

# Test the function
assert digit_distance_nums(1,2) == 1
assert digit_distance_nums(12,23) == 4
assert digit_distance_nums(123,234) == 6
assert digit_distance_nums(1234,2345) == 8

microsoft--Phi-3-mini-4k-instruct. fail_base: False, fail_plus: True

  def digit_distance_nums(num1, num2):
    """
    Find the sum of the per-digit difference between two integers.

    Args:
    num1 (int): The first integer.
    num2 (int): The second integer.

    Returns:
    int: The sum of the per-digit difference between the two integers.

    Example:
    >>> digit_distance_nums(1, 2)
    1
    >>> digit_distance_nums(123, 456)
    9
    """
    # Convert the numbers to strings to iterate over their digits
    str_num1, str_num2 = str(num1), str(num2)

    # Ensure the numbers have the same number of digits
    if len(str_num1) != len(str_num2):
        raise ValueError("Numbers must have the same number of digits.")

    # Calculate the sum of the per-digit differences
    sum_diff = sum(abs(int(digit1) - int(digit2)) for digit1, digit2 in zip(str_num1, str_num2))

    return sum_diff

# Test cases
assert digit_distance_nums(1, 2) == 1
assert digit_distance_nums(123, 456) == 9
assert digit_distance_nums(100, 200) == 100
assert digit_distance_nums(12345, 67890) == 25

speechless-codellama-34b. fail_base: False, fail_plus: True

  def digit_distance_nums(num1, num2):
    # Convert the integers to strings to access individual digits
    str_num1 = str(num1)
    str_num2 = str(num2)
    
    # Initialize the sum variable
    sum_diff = 0
    
    # Iterate through the digits of the two numbers
    for i in range(len(str_num1)):
        # Calculate the absolute difference between the digits
        diff = abs(int(str_num1[i]) - int(str_num2[i]))
        
        # Add the difference to the sum
        sum_diff += diff
    
    # Return the final sum
    return sum_diff

# Test the function with the given example
assert digit_distance_nums(1, 2) == 1
```

meta-llama-3-70b-instruct. fail_base: False, fail_plus: True

  def digit_distance_nums(a, b):
    a_str = str(a)
    b_str = str(b)
    max_len = max(len(a_str), len(b_str))
    a_str = a_str.zfill(max_len)
    b_str = b_str.zfill(max_len)
    return sum(abs(int(x) - int(y)) for x, y in zip(a_str, b_str))

assert digit_distance_nums(1,2) == 1

stable-code-3b. fail_base: False, fail_plus: False

  """
Write a python function to find the sum of the per-digit difference between two integers.
assert digit_distance_nums(1,2) == 1
"""

def digit_distance_nums(num1, num2):
    return sum(abs(int(i) - int(j)) for i, j in zip(str(num1), str(num2)))

print(digit_distance_nums(1,2))

"""
Write a python function to find the sum of the per-digit difference between two integers.
assert digit_distance_nums(1,2) == 1
"""

def digit_distance_nums(num1, num2):
    return sum(abs(int(i) - int(j)) for i, j in zip(str(num1), str(num2)))

print(digit_distance_nums(1,2))

"""
Write a python function to find the sum of the per-digit difference between two integers.
assert digit_distance_nums(1,2) == 1
"""

def digit_distance_nums(num1, num2):
    return sum(abs(int(i) - int(j)) for i, j in zip(str(num1), str(num2)))

print(digit_distance_nums(1,2))

"""
Write a python function to find the sum of the per-digit difference between two integers.
assert digit_distance_nums(1,2) == 1
"""

def digit_distance_nums(num1, num2):
    return sum(abs(int(i) - int(j)) for i, j in zip(str(num1), str(num2)))

print(digit_distance_nums(1,2))

"""
Write a python function to find the sum of the per-digit difference between two integers.
assert digit_distance_nums(1,2) == 1
"""

def digit_distance_nums(num1, num2):
    return sum(abs(int(i) - int(j)) for i, j in zip(str(num1), str(num2)))

print(digit_distance_nums(1,2))

"""
Write a python function to find the sum of the per-digit difference between two integers.
assert digit_distance_nums(1,2) == 1

codegen-6b. fail_base: True, fail_plus: True

  """
Write a python function to find the sum of the per-digit difference between two integers.
assert digit_distance_nums(1,2) == 1
"""

def digit_distance_nums(num1, num2):
    """
    Return the sum of the per-digit difference between two integers.
    """
    num1_str = str(num1)
    num2_str = str(num2)
    num1_len = len(num1_str)
    num2_len = len(num2_str)
    if num1_len > num2_len:
        num1_str = num1_str[:num2_len]
    elif num2_len > num1_len:
        num2_str = num2_str[:num1_len]
    num1_str = int(num1_str)
    num2_str = int(num2_str)
    num1_str = str(num1_str)
    num2_str = str(num2_str)
    num1_len = len(num1_str)
    num2_len = len(num2_str)
    num1_str = num1_str[::-1]
    num2_str = num2_str[::-1]
    num1_str = int(num1_str)
    num2_str = int(num2_str)
    num1_str = str(num1_str)
    num2_str = str(num2_str)
    num1_len = len(num1_str)
    num2_len = len(num2_str)
    num1_str = num1_str[::-1]
    num2_str = num2_str[::-1]
    num1_str = int(num1_str)
    num2_str = int(num2_str)
    num1_str = str(num1_str)
    num2_str = str(num2_str)
    num1_len = len(num1_str)
    num2_len = len(num2_str)
    num1_str = num1_str[::-1]
    num2_str = num2_str[::-1]
    num1_str = int(num1_str

gpt-4-1106-preview. fail_base: False, fail_plus: True

  """
Write a python function to find the sum of the per-digit difference between two integers.
assert digit_distance_nums(1,2) == 1
"""



def digit_distance_nums(num1, num2):
    str_num1, str_num2 = str(num1), str(num2)
    if len(str_num1) != len(str_num2):
        raise ValueError('Numbers must have the same number of digits')

    return sum(abs(int(d1) - int(d2)) for d1, d2 in zip(str_num1, str_num2))

# Example usage:
# result = digit_distance_nums(123, 321)
# print(result)  # Output: 4 (|1-3| + |2-2| + |3-1|)

# Test case:
assert digit_distance_nums(1, 2) == 1

gemma-7b-it. fail_base: True, fail_plus: True

  def digit_distance_nums(num1, num2):
    # Convert both numbers to strings
    num1_str = str(num1)
    num2_str = str(num2)

    # Find the sum of the per-digit difference
    sum = 0
    for i in range(len(num1_str)):
        digit1 = int(num1_str[i])
        for j in range(len(num2_str)):
            digit2 = int(num2_str[j])
            distance = abs(digit1 - digit2)
            sum += distance

    # Return the sum
    return sum

opencodeinterpreter-ds-33b. fail_base: False, fail_plus: True

  ```python
def digit_distance_nums(num1, num2):
    num1_str = str(num1)
    num2_str = str(num2)
    max_len = max(len(num1_str), len(num2_str))
    num1_str = num1_str.zfill(max_len)
    num2_str = num2_str.zfill(max_len)
    sum_diff = 0
    for i in range(max_len):
        sum_diff += abs(int(num1_str[i]) - int(num2_str[i]))
    return sum_diff

# Test the function
print(digit_distance_nums(1,2))

openchat. fail_base: False, fail_plus: True

  def digit_distance_nums(num1, num2):
    # Convert the numbers to strings to easily access each digit
    num1_str = str(num1)
    num2_str = str(num2)

    # Initialize the sum of the per-digit differences
    sum_of_differences = 0

    # Loop through each digit in the numbers
    for i in range(len(num1_str)):
        # Calculate the difference between the corresponding digits
        difference = abs(int(num1_str[i]) - int(num2_str[i]))
        # Add the difference to the sum of the per-digit differences
        sum_of_differences += difference

    return sum_of_differences

# Test the function
assert digit_distance_nums(1, 2) == 1

speechless-starcoder2-7b. fail_base: False, fail_plus: True

  def digit_distance_nums(num1, num2):
    # Convert the numbers to strings
    str_num1 = str(num1)
    str_num2 = str(num2)

    # Find the length of the strings
    len_num1 = len(str_num1)
    len_num2 = len(str_num2)

    # If the lengths are not equal, pad the shorter string with zeros
    if len_num1 < len_num2:
        str_num1 = str_num1.zfill(len_num2)
    elif len_num2 < len_num1:
        str_num2 = str_num2.zfill(len_num1)

    # Calculate the sum of the absolute differences between corresponding digits
    sum_diff = sum(abs(int(str_num1[i]) - int(str_num2[i])) for i in range(len(str_num1)))

    return sum_diff

# Test the function
assert digit_distance_nums(1,2) == 1

wizardcoder-7b. fail_base: True, fail_plus: True

  Here's the Python function to find the sum of the per-digit difference between two integers:

```python
def digit_distance_nums(num1, num2):
    # Convert the numbers to strings to be able to iterate over each digit
    num1_str = str(num1)
    num2_str = str(num2)
    
    # Initialize the sum variable to 0
    sum = 0
    
    # Iterate over each digit in the numbers
    for i in range(max(len(num1_str), len(num2_str)):
        # If the digit is not present in the other number, set it to 0
        if i >= len(num2_str):
            num2_str += '0'
        if i >= len(num1_str):
            num1_str += '0'
        
        # Calculate the difference between the digits and add it to the sum
        sum += abs(int(num1_str[i]) - int(num2_str[i]))
    
    return sum
```

This function first converts the input numbers to strings so that we can iterate over each digit. It then initializes a sum variable to 0 and iterates over each digit in the longer number. If a digit is not present in the other number, it sets it to 0. It calculates the difference between the digits and adds it to the sum. Finally, it returns the sum. 

octocoder. fail_base: False, fail_plus: False

  """
Write a python function to find the sum of the per-digit difference between two integers.
assert digit_distance_nums(1,2) == 1
"""


def digit_distance_nums(num1, num2):
    """
    Returns the sum of the per-digit difference between two integers.
    """
    return sum(abs(int(i) - int(j)) for i, j in zip(str(num1), str(num2)))

gemma-1.1-7b-it. fail_base: False, fail_plus: False

  def digit_distance_nums(num1, num2):
    """
    Finds the sum of the per-digit difference between two integers.
    """
    distance = 0
    
    # Convert both numbers to strings
    str1 = str(num1)
    str2 = str(num2)
    
    # Iterate over each digit in both strings
    for i in range(len(str1)):
        if i < len(str2) and str1[i] != str2[i]:
            distance += abs(int(str1[i]) - int(str2[i]))
    
    return distance

assert digit_distance_nums(1,2) == 1

deepseek-coder-6.7b-base. fail_base: False, fail_plus: True

  """
Write a python function to find the sum of the per-digit difference between two integers.
assert digit_distance_nums(1,2) == 1
"""


def digit_distance_nums(num1, num2):
    num1 = str(num1)
    num2 = str(num2)
    sum = 0
    for i in range(len(num1)):
        sum += abs(int(num1[i]) - int(num2[i]))
    return sum


print(digit_distance_nums(1, 2))

codegen-16b. fail_base: True, fail_plus: True

  """
Write a python function to find the sum of the per-digit difference between two integers.
assert digit_distance_nums(1,2) == 1
"""

def digit_distance_nums(num1, num2):
    """
    :param num1:
    :param num2:
    :return:
    """
    num1_str = str(num1)
    num2_str = str(num2)
    num1_list = [int(i) for i in num1_str]
    num2_list = [int(i) for i in num2_str]
    num1_list.sort()
    num2_list.sort()
    num1_list_len = len(num1_list)
    num2_list_len = len(num2_list)
    if num1_list_len!= num2_list_len:
        return -1
    else:
        num1_list_len = len(num1_list)
        num2_list_len = len(num2_list)
        num1_list_len = len(num1_list)
        num2_list_len = len(num2_list)
        num1_list_len = len(num1_list)
        num2_list_len = len(num2_list)
        num1_list_len = len(num1_list)
        num2_list_len = len(num2_list)
        num1_list_len = len(num1_list)
        num2_list_len = len(num2_list)
        num1_list_len = len(num1_list)
        num2_list_len = len(num2_list)
        num1_list_len = len(num1_list)
        num2_list_len = len(num2_list)
        num1_list_len = len(num1_list)
        num2_list_len = len(num2_list)
        num1_list_len = len(num1_list)
        num2_list_len = len(num2_list)
        num1_list_len = len(num1_list)
        num2_list_len = len(num2_list)
        num1_list_len = len(num

mistral-7b. fail_base: False, fail_plus: True

  """
Write a python function to find the sum of the per-digit difference between two integers.
assert digit_distance_nums(1,2) == 1
"""


def digit_distance_nums(num1, num2):
    num1 = str(num1)
    num2 = str(num2)
    if len(num1) != len(num2):
        return "The numbers must be of the same length"
    else:
        sum = 0
        for i in range(len(num1)):
            sum += abs(int(num1[i]) - int(num2[i]))
        return sum


print(digit_distance_nums(1, 2))

speechless-mistral-7b. fail_base: False, fail_plus: True

  def digit_distance_nums(num1, num2):
    num1 = str(num1)
    num2 = str(num2)
    if len(num1) != len(num2):
        return "Error: Numbers must have the same number of digits."
    else:
        sum_diff = 0
        for i in range(len(num1)):
            diff = abs(int(num1[i]) - int(num2[i]))
            sum_diff += diff
        return sum_diff

assert digit_distance_nums(1,2) == 1
```

This Python function takes two integers as input, converts them to strings, and then compares each digit of the two numbers. If the digits are different, it calculates the absolute difference between them and adds it to a running total. If the numbers have different lengths, it returns an error message. The function finally returns the total sum of the per-digit differences.

codet5p-16b. fail_base: False, fail_plus: False

  """
Write a python function to find the sum of the per-digit difference between two integers.
assert digit_distance_nums(1,2) == 1
"""


def digit_distance_nums(num1, num2):
    return sum([abs(int(i) - int(j)) for i, j in zip(str(num1), str(num2))])

assert digit_distance_nums(1,2) == 1
assert digit_distance_nums(1,3) == 2
assert digit_distance_nums(1,4) == 3
assert digit_distance_nums(1,5) == 4
assert digit_distance_nums(1,6) == 5
assert digit_distance_nums(1,7) == 6
assert digit_distance_nums(1,8) == 7
assert digit_distance_nums(1,9) == 8
assert digit_distance_nums(1,10) == 9
assert digit_distance_nums(1,11) == 10
assert digit_distance_nums(1,12) == 11
assert digit_distance_nums(1,13) == 12
assert digit_distance_nums(1,14) == 13
assert digit_distance_nums(1,15) == 14
assert digit_distance_nums(1,16) == 15
assert digit_distance_nums(1,17) == 16
assert digit_distance_nums(1,18) == 17
assert digit_distance_nums(1,19) == 18
assert digit_distance_nums(1,20) == 19
assert digit_distance_nums(1,21) == 20
assert digit_distance_nums(1,22) == 21
assert digit_distance_nums(1,23) == 22
assert digit_distance_nums(1,24) == 23
assert digit_distance_nums(1,25) == 24
assert digit_distance_nums(1,26) == 25
assert digit_distance_nums(1,27) == 26
assert digit_distance_nums(1,28) == 27
assert digit_distance_nums(1,29) == 28
assert digit_distance_nums(1,30) == 29
assert digit_distance_nums(1,31) == 30
assert digit_distance_nums(1,32

code-llama-13b. fail_base: False, fail_plus: True

  """
Write a python function to find the sum of the per-digit difference between two integers.
assert digit_distance_nums(1,2) == 1
"""

def digit_distance_nums(num1, num2):
    sum = 0
    for i in range(len(str(num1))):
        sum += abs(int(str(num1)[i]) - int(str(num2)[i]))
    return sum

print(digit_distance_nums(1,2))
print(digit_distance_nums(123,456))
print(digit_distance_nums(12345,6789))

xdan-l1-chat. fail_base: False, fail_plus: True

  def digit_distance_nums(num1, num2):
    """
    Calculates the sum of the per-digit difference between two integers.
    """
    if num1 < num2:
        num1, num2 = num2, num1
    
    result = 0
    for i in range(len(str(num1))):
        digit1 = num1 % 10
        digit2 = num2 % 10
        result += abs(digit1 - digit2)
        num1 //= 10
        num2 //= 10
    
    return result

# Test the function
assert digit_distance_nums(1, 2) == 1

solar-10.7b-instruct. fail_base: False, fail_plus: True

  """
Write a python function to find the sum of the per-digit difference between two integers.
assert digit_distance_nums(1,2) == 1
"""
def digit_distance_nums(num1, num2):
    num1_str = str(num1)
    num2_str = str(num2)
    result = 0

    if len(num1_str) != len(num2_str):
        raise ValueError("Both numbers must have the same number of digits.")

    for i in range(len(num1_str)):
        result += abs(int(num1_str[i]) - int(num2_str[i]))

    return result

assert digit_distance_nums(1, 2) == 1

gemma-2b. fail_base: False, fail_plus: True

  """
Write a python function to find the sum of the per-digit difference between two integers.
assert digit_distance_nums(1,2) == 1
"""


def digit_distance_nums(a, b):
    """
    :param a:
    :param b:
    :return:
    """
    a = str(a)
    b = str(b)
    a_list = list(a)
    b_list = list(b)
    a_list.sort()
    b_list.sort()
    a_list = [int(i) for i in a_list]
    b_list = [int(i) for i in b_list]
    a_list.sort()
    b_list.sort()
    return sum(abs(a_list[i] - b_list[i]) for i in range(len(a_list)))

claude-3-sonnet-20240229. fail_base: False, fail_plus: True

  Here's the Python code to solve the problem, wrapped in a Python markdown block:

```python
"""
Write a python function to find the sum of the per-digit difference between two integers.
assert digit_distance_nums(1,2) == 1
"""

def digit_distance_nums(num1, num2):
    """
    Finds the sum of the per-digit difference between two integers.
    
    Args:
        num1 (int): The first integer.
        num2 (int): The second integer.
        
    Returns:
        int: The sum of the per-digit difference between num1 and num2.
    """
    # Convert the integers to strings and pad with leading zeros to ensure equal length
    num1_str = str(num1).zfill(max(len(str(num1)), len(str(num2))))
    num2_str = str(num2).zfill(max(len(str(num1)), len(str(num2))))
    
    # Initialize the sum to 0
    digit_sum = 0
    
    # Iterate over the digits and calculate the per-digit difference
    for i in range(len(num1_str)):
        digit_sum += abs(int(num1_str[i]) - int(num2_str[i]))
    
    return digit_sum

# Test cases
assert digit_distance_nums(1, 2) == 1
assert digit_distance_nums(123, 456) == 6
assert digit_distance_nums(1000, 1) == 997
print("All test cases passed!")

starcoder2-15b-oci. fail_base: False, fail_plus: False

  """
Write a python function to find the sum of the per-digit difference between two integers.
assert digit_distance_nums(1,2) == 1
"""


def digit_distance_nums(num1, num2):
    return sum(abs(int(digit1) - int(digit2)) for digit1, digit2 in zip(str(num1), str(num2)))

starcoder2-3b. fail_base: False, fail_plus: True

  """
Write a python function to find the sum of the per-digit difference between two integers.
assert digit_distance_nums(1,2) == 1
"""

def digit_distance_nums(num1, num2):
    num1 = str(num1)
    num2 = str(num2)
    if len(num1) != len(num2):
        return None
    else:
        sum = 0
        for i in range(len(num1)):
            sum += abs(int(num1[i]) - int(num2[i]))
        return sum

print(digit_distance_nums(1,2))
print(digit_distance_nums(1,23))
print(digit_distance_nums(1,234))
print(digit_distance_nums(1,2345))
print(digit_distance_nums(1,23456))
print(digit_distance_nums(1,234567))
print(digit_distance_nums(1,2345678))
print(digit_distance_nums(1,23456789))
print(digit_distance_nums(1,234567890))
print(digit_distance_nums(1,2345678901))
print(digit_distance_nums(1,23456789012))
print(digit_distance_nums(1,234567890123))
print(digit_distance_nums(1,2345678901234))
print(digit_distance_nums(1,23456789012345))
print(digit_distance_nums(1,234567890123456))
print(digit_distance_nums(1,2345678901234567))
print(digit_distance_nums(1,23456789012345678))
print(digit_distance_nums(1,234567890123456789))
print(digit_distance_nums(1,2345678901234567890))
print(

speechless-starcoder2-15b. fail_base: True, fail_plus: True

  def digit_distance_nums(num1, num2):
    return sum(abs(int(str(num1)[i])) - int(str(num2)[i])) for i in range(max(len(str(num1))), len(str(num2)))))

assert digit_distance_nums(1,2) == 1

gemma-7b. fail_base: False, fail_plus: True

  """
Write a python function to find the sum of the per-digit difference between two integers.
assert digit_distance_nums(1,2) == 1
"""


def digit_distance_nums(num1, num2):
    num1 = str(num1)
    num2 = str(num2)
    if len(num1) != len(num2):
        return "The two numbers must be the same length."
    else:
        sum = 0
        for i in range(len(num1)):
            sum += abs(int(num1[i]) - int(num2[i]))
        return sum

opencodeinterpreter-ds-6.7b. fail_base: False, fail_plus: True

  ```python
def digit_distance_nums(num1, num2):
    # Convert the numbers to strings
    str_num1 = str(num1)
    str_num2 = str(num2)

    # Find the length of the longer string
    length = max(len(str_num1), len(str_num2))

    # Initialize the sum of the per-digit differences
    sum_diff = 0

    # Iterate over the digits of the numbers
    for i in range(length):
        # Get the digit at position i for num1 and num2
        digit1 = int(str_num1[i]) if i < len(str_num1) else 0
        digit2 = int(str_num2[i]) if i < len(str_num2) else 0

        # Calculate the absolute difference between the digits
        diff = abs(digit1 - digit2)

        # Add the difference to the sum
        sum_diff += diff

    return sum_diff

# Test the function
assert digit_distance_nums(1,2) == 1