"""
Write a function to merge three dictionaries into a single dictionary.
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
"""
import collections as ct
def merge_dictionaries_three(dict1,dict2, dict3):
merged_dict = dict(ct.ChainMap({},dict1,dict2,dict3))
return merged_dict
[[{'R': 'Red', 'P': 'Pink'}, {'G': 'Green'}, {'O': 'Orange', 'W': 'White', 'B': 'Black'}], [{'R': 'Red', 'P': 'Pink'}, {'G': 'Green', 'W': 'White'}, {'L': 'lavender', 'B': 'Blue'}], [{'R': 'Red', 'P': 'Pink'}, {'L': 'lavender', 'B': 'Blue'}, {'G': 'Green', 'W': 'White'}]] [[{}, {}, {}], [{}, {'A': 'Apple'}, {}], [{'A': 'Apple'}, {}, {}], [{}, {}, {'A': 'Apple'}], [{'A': {'B': {'C': {'D': 'Apple'}}}}, {}, {}], [{'R': {'B': {'P': {'M': 'Red'}}}}, {'L': {'B': 'Blue'}}, {'G': {'W': 'Green'}}], [{}, {'A': {'X': {'Y': {'Z': 'Apple'}}}}, {}], [{'R': {'B': {'P': {'M': 'Red'}}}}, {'G': {'W': 'White'}}, {'L': {'B': 'Blue'}}], [{'-20.518312632449252': -16, '-0.31776260008138024': 65}, {}, {}], [{'A': {'B': {'C': {'D': 'Apple'}}}}, {'B': 'yS', 'bXTSGefP': 'zqKImWxAN'}, {}], [{}, {'-59': -20.518312632449252, '65': -16}, {}], [{}, {'A': 'C', 'W': 'Appple'}, {}], [{}, {'-59': -20.518312632449252, '65': -16}, {'-73.06068215185819': 37, '-20.518312632449252': -49, '-50.80098800326578': -49}], [{'-24.325512454128287': 'ngwPYYUsW', '-0.31776260008138024': 'R', '64.10081127712078': ''}, {}, {}], [{'-24.325512454128287': 'ngwPYYUsW', '-0.31776260008138024': 'R', '64.10081127712078': ''}, {}, {'-34': True, '-86': -73.06068215185819, '74': {'37': False, '-95': False, '58': True, '65': True, '-85': True, '98': False, '51': True}, '-61': None, '-49': 'CjqqZMMy', '-47': -16, '65': 'D', '-59': True}], [{}, {'W': 'bXTSGefP'}, {}], [{}, {'A': {}, 'MA': {}, 'AMA': {'HzgYlcGpOG': 'White', 'ZfhiHxlH': 'Y', 'lCjSZS': 'C', 'x': 'ngwPYYUsW', 'Green': '', 'A': 'ngwPYYPUsW'}, 'MAA': {'HzgYlcGpOG': 'White', 'ZfhiHxlH': 'Y', 'lCjSZS': 'C', 'x': 'ngwPYYUsW', 'Green': '', 'A': 'ngwPYYPUsW'}}, {}], [{}, {'-59': -20.518312632449252}, {}], [{'R': {'B': {'P': {'M': 'Red', 'DM': 'R'}}, '': {'P': {'M': 'Red', 'DM': 'R'}}}}, {}, {'G': {'W': 'White', 'WW': 'WHzgYlcGpOGhite'}, 'GG': {'W': 'White', 'WW': 'WHzgYlcGpOGhite'}}], [{}, {}, {'-17': False, '98': True, '-49': False, '35': True}], [{}, {}, {'-17': False, '98': True, '-49': False, '35': True}], [{'A': {'B': {'C': {'D': 'Appe'}}, 'Red': {'C': {'D': 'Appe'}}}}, {'B': 'yS', 'bXTSGefP': 'zqKImWxAN'}, {}], [{}, {'false': 'IANrUc', '-55': '', '-16': 'BdGTYTf', '-47': 'b', '87': 'HTv', '81': 'Green', '-59': 'yS', '65': 'AYC'}, {'A': {'B': {'C': {'D': 'Appe', 'Appe': 'lCjSZS'}}, 'Red': {'C': {'D': 'Appe', 'Appe': 'lCjSZS'}}, 'BlueB': {'C': {'D': 'Appe', 'Appe': 'lCjSZS'}}}, 'P': {'B': {'C': {'D': 'Appe', 'Appe': 'lCjSZS'}}, 'Red': {'C': {'D': 'Appe', 'Appe': 'lCjSZS'}}, 'BlueB': {'C': {'D': 'Appe', 'Appe': 'lCjSZS'}}}}], [{}, {}, {'-73.06068215185819': 37, '-20.518312632449252': -49, '-50.80098800326578': -49}], [{'-24.325512454128287': 'ngwPYYUsW', '-0.31776260008138024': 'R', '64.10081127712078': '', '-20.518312632449252': 'ngwPYYPUsW'}, {}, {'-34': True, '-86': -73.06068215185819, '74': {'37': False, '-95': False, '58': True, '65': True, '-85': True, '98': False, '51': True}, '-61': None, '-49': 'CjqqZMMy', '-47': -16, '65': 'D', '-59': True, '58': -16}], [{}, {}, {'-20.518312632449252': -16, '-0.31776260008138024': 65}], [{}, {'-59': -50.80098800326578}, {'-56': -95, '27': True}], [{}, {'R': {}, 'RR': {}}, {'G': {'W': 'White'}}], [{'ayuEVhTX': 'C', 'apglGpJ': 'klLihKVK', 'P': 'Awnq', 'OvdlVN': 'P', 'ngwPYYUsW': 'Y', 'W': 'Luto'}, {}, {'-17': False, '98': False, '-49': False, '35': False}], [{}, {}, {'-17': False, '-49': True, '35': False}], [{}, {'-50.80098800326578': -37.99257891277086, '-24.325512454128287': 70.78935461953051, '-0.31776260008138024': -50.80098800326578, '-50.392470117934096': -20.518312632449252}, {}], [{'35': -59}, {'R': {'B': {'P': {'M': 'Red', 'lCjSZS': 'RRed'}}}, 'Red': {'B': {'P': {'M': 'Red', 'lCjSZS': 'RRed'}}}}, {}], [{'D': 97, 'MAA': 56, 'HTv': 65}, {'42.54365262109431': 12, '-73.06068215185819': 99, '64.10081127712078': False, '-71.19218925050797': -27.722667031889188, '-70.6746308928394': 83.83304478046807}, {'IWhN': 'V'}], [{'37': False}, {}, {'NH': True, 'CjqqZMMy': True, 'ngwPYYUsW': False, 'ORPBKquP': False, 'XryExq': True, 'DVeAQTRIZV': False, 'Z': True, 'Red': False, 'Y': False, 'White': False}], [{'A': 'Apple'}, {'btabmgZJMp': 'bkk'}, {}], [{'D': 97, 'MAA': 56, 'HTv': 65}, {'42.54365262109431': 37, '-73.06068215185819': 99, '64.10081127712078': False, '-71.19218925050797': -27.722667031889188, '-70.6746308928394': 83.83304478046807}, {'IWhN': 'V'}], [{}, {'-59': -20.518312632449252}, {'BlueB': 'B', 'GyqTxRqw': 'IWhN', 'apglGpJ': 'TkzQdZezp'}], [{'R': {'B': {'P': {'M': 'Red', 'DM': 'R', 'MDM': 'RR'}, 'White': {'M': 'Red', 'DM': 'R', 'MDM': 'RR'}}, '': {'P': {'M': 'Red', 'DM': 'R', 'MDM': 'RR'}, 'White': {'M': 'Red', 'DM': 'R', 'MDM': 'RR'}}, 'WW': {'P': {'M': 'Red', 'DM': 'R', 'MDM': 'RR'}, 'White': {'M': 'Red', 'DM': 'R', 'MDM': 'RR'}}}, '': {'B': {'P': {'M': 'Red', 'DM': 'R', 'MDM': 'RR'}, 'White': {'M': 'Red', 'DM': 'R', 'MDM': 'RR'}}, '': {'P': {'M': 'Red', 'DM': 'R', 'MDM': 'RR'}, 'White': {'M': 'Red', 'DM': 'R', 'MDM': 'RR'}}, 'WW': {'P': {'M': 'Red', 'DM': 'R', 'MDM': 'RR'}, 'White': {'M': 'Red', 'DM': 'R', 'MDM': 'RR'}}}}, {}, {'G': {'W': 'White', 'WW': 'WHzgYlcGpOGhite'}, 'GG': {'W': 'White', 'WW': 'WHzgYlcGpOGhite'}}], [{}, {}, {'-50.80098800326578': -37.99257891277086, '-24.325512454128287': 70.78935461953051, '-0.31776260008138024': -50.80098800326578, '-50.392470117934096': -20.518312632449252, '-73.06068215185819': 42.54365262109431, '-24.096762660953626': 71.37539857958085, '-23.830002499577663': -19.83610846406233}], [{'R': {'B': {'P': {'M': 'Red', 'DM': 'R', 'MDM': 'RR'}, 'White': {'M': 'Red', 'DM': 'R', 'MDM': 'RR'}}, '': {'P': {'M': 'Red', 'DM': 'R', 'MDM': 'RR'}, 'White': {'M': 'Red', 'DM': 'R', 'MDM': 'RR'}}, 'WW': {'P': {'M': 'Red', 'DM': 'R', 'MDM': 'RR'}, 'White': {'M': 'Red', 'DM': 'R', 'MDM': 'RR'}}}, '': {'B': {'P': {'M': 'Red', 'DM': 'R', 'MDM': 'RR'}, 'White': {'M': 'Red', 'DM': 'R', 'MDM': 'RR'}}, '': {'P': {'M': 'Red', 'DM': 'R', 'MDM': 'RR'}, 'White': {'M': 'Red', 'DM': 'R', 'MDM': 'RR'}}, 'WW': {'P': {'M': 'Red', 'DM': 'R', 'MDM': 'RR'}, 'White': {'M': 'Red', 'DM': 'R', 'MDM': 'RR'}}}}, {}, {'G': {'W': 'White', 'WW': 'WHzgYlcGpOGhite'}}], [{'37': False}, {'17.73931516433271': 'oxcd', '42.54365262109431': 23.795747795363283}, {'NH': True, 'CjqqZMMy': True, 'ngwPYYUsW': False, 'ORPBKquP': False, 'XryExq': True, 'DVeAQTRIZV': False, 'Z': True, 'Red': False, 'Y': False, 'White': False}], [{'-59': -20.518312632449252}, {'-3.700287742454634': False, '-38.26014318376585': None, '17.73931516433271': False, '62.77802727777075': ['apglGpJ', 'bz', 'DM', 'bN', 'BlueB', 'lwkww', 'IITWMS', 'DVeAQTRIZV'], '-67.57915780584574': 37.65070836123044, '-50.80098800326578': 'Awnq', '-71.19218925050797': -1.1152135632978002, '-70.6746308928394': -54.08169240148757}, {}], [{}, {}, {'A': {}, 'MA': {'-61.83059892834244': -21.3703814092123, '-74.60156534154282': 64.10081127712078, '17.73931516433271': -67.57915780584574}, 'AMA': {'ZfhiHxlH': 'Y', 'lCjSZS': 'C', 'x': 'ngwPYYUsW', 'Green': '', 'A': 'ngwPYYPUsW'}, 'MORPBKquPA': {'-67.57915780584574': -68, '70.78935461953051': 15, '89.92770337658328': 2, '-40.8169187894486': 20, '-53.026275322982166': -16, '64.10081127712078': 98, '-50.392470117934096': -4, '-89.55492254635429': 35}, 'OvdlVN': {'ZfhiHxlH': 'Y', 'lCjSZS': 'C', 'x': 'ngwPYYUsW', 'Green': '', 'A': 'ngwPYYPUsW'}}], [{'37': False}, {'17.73931516433271': 'oxcd', '42.54365262109431': 23.795747795363283}, {'NH': True, 'CjqqZMMy': True, 'ngwPYYUsW': False, 'ORPBKquP': False, 'XryExq': True, 'DVeAQTRIZV': False, 'Z': True, 'Red': False, 'Y': False, 'White': True}], [{}, {'W': 'bXTSGefP', 'OvdlVN': 'bXTSefP'}, {}], [{'-81.67842976641': 'Red', '-61.83059892834244': 'oxcd', '-21.3703814092123': 'V', '92.50540451758502': 'GG', '-27.722667031889188': 'NubHsqVl', '-53.026275322982166': 'Y', '89.92770337658328': 'ayuEVhTX', '-24.096762660953626': 'Awnq', '-53.805001572422206': 'VyMQgZV'}, {}, {'-17': False, '-49': False, '35': True}], [{}, {}, {'-17': False, '35': False}], [{'-59': -20.518312632449252, '65': -16}, {}, {}], [{}, {'-59': -50.80098800326578}, {}], [{}, {}, {'ayuEVhTX': 'C', 'apglGpJ': 'klLihngwPYYUsWKVK', 'P': 'Awnq', 'OvdlVN': 'P', 'ngwPYYUsW': 'Y', 'W': 'Luto'}], [{'-81.67842976641': 'Red', '-61.83059892834244': 'oxcd', '-21.3703814092123': 'V', '92.50540451758502': 'GG', '-27.722667031889188': 'NubHsqVl', '-53.026275322982166': 'Y', '89.92770337658328': 'ayuEVhTX', '-24.096762660953626': 'Awnq'}, {}, {'-17': False, '-49': False, '35': True}], [{}, {}, {'-34': True, '-86': -73.06068215185819, '74': {'37': False, '-95': False, '58': True, '65': True, '-85': True, '98': False, '51': True}, '-61': None, '-49': 'CjqqZMMy', '-47': -16, '65': 'D', '-59': True, '58': -16, '35': -73.71456655267669}], [{}, {'17.73931516433271': 'oxcd', '42.54365262109431': 23.795747795363283, '-53.805001572422206': 23.72761067835703}, {'37': False}], [{}, {'-81.67842976641': 'Red', '-61.83059892834244': 'oxcd', '-21.3703814092123': 'V', '92.50540451758502': 'GG', '-27.722667031889188': 'NubHsqVl', '-53.026275322982166': 'Y', '89.92770337658328': 'ayuEVhTX', '-24.096762660953626': 'Awnq'}, {'-17': True, '35': True, '-50': False}], [{}, {}, {'A': {}, 'MA': {'-61.83059892834244': -21.3703814092123, '-74.60156534154282': 64.10081127712078}, 'AMA': {'ZfhiHxlH': 'Y', 'lCjSZS': 'C', 'x': 'ngwPYYUsW', 'Green': '', 'A': 'ngwPYYPUsW'}, 'MORPBKquPA': {'-67.57915780584574': -68, '70.78935461953051': 15, '89.92770337658328': 2, '-40.8169187894486': 20, '-53.026275322982166': -16, '64.10081127712078': 98, '-50.392470117934096': -4, '-89.55492254635429': 35}, 'OvdlVN': {'ZfhiHxlH': 'Y', 'lCjSZS': 'C', 'x': 'ngwPYYUsW', 'Green': '', 'A': 'ngwPYYPUsW'}}], [{'-59': -20.518312632449252, '65': -16, '-17': -89.55492254635429}, {}, {}], [{'D': 97, 'MAA': 56, 'HTv': 65}, {'42.54365262109431': 37, '-73.06068215185819': 99, '64.10081127712078': False, '-71.19218925050797': -27.722667031889188, '-70.6746308928394': 83.83304478046807}, {'IWhN': 'V', 'IWGhN': 'lCjSZS'}], [{}, {}, {'-17': True, '35': False, '36': True}], [{'-22.979929602255183': False, '-53.805001572422206': True, '-91.20082277315413': False, '-24.325512454128287': False, '-96.49581018651745': True}, {'-59': -20.518312632449252, '65': -16}, {'98': 'lCjSZS', '-61': 'BdGTYTf', '-83': 'IITWMS', '99': 'cU', '-55': 'bkk', '-80': 'Red', '-16': 'Xhr'}], [{'D': 97, 'MAA': 56, 'HTv': 65}, {'42.54365262109431': 37, '-73.06068215185819': 99, '64.10081127712078': False, '-71.19218925050797': -27.722667031889188, '-70.6746308928394': 83.83304478046807, '-72.6127463653807': False}, {'IWhN': 'V'}], [{}, {}, {'-17': False, '98': False, '-49': False, '35': True}], [{}, {'false': 'IANrUc', '-55': '', '-16': 'BdGTYTf', '87': 'HTv', '81': 'Green', '-59': 'yS', '65': 'AYC'}, {'A': {'B': {'C': {'D': 'Appe', 'Appe': 'lCjSZS'}}, 'Red': {'C': {'D': 'Appe', 'Appe': 'lCjSZS'}}, 'BlueB': {'C': {'D': 'Appe', 'Appe': 'lCjSZS'}}}, 'P': {'B': {'C': {'D': 'Appe', 'Appe': 'lCjSZS'}}, 'Red': {'C': {'D': 'Appe', 'Appe': 'lCjSZS'}}, 'BlueB': {'C': {'D': 'Appe', 'Appe': 'lCjSZS'}}}}], [{'-26.51617320630959': 70.78935461953051, '-81.67842976641': -30.321108218462143, '46.636170318669855': -96.49581018651745, '27.84449804744338': 42.54365262109431, '-63.86477732020253': -50.80098800326578, '-87.04295405175097': -42.95773384196735, '92.7915796198375': 17.73931516433271, '56.10336306263682': 54.480351980114875, '-30.818290306420366': -19.83610846406233, '-31.734037590181316': -91.20082277315413}, {}, {'-17': False, '98': False, '-49': False, '35': True, '36': False}], [{}, {'A': 'C', 'W': 'klLihKVK'}, {}], [{}, {'D': 97, 'MAA': 56}, {'IWhN': ''}], [{}, {'-17': False, '-49': False, '35': True}, {'-81.67842976641': 'Red', '-61.83059892834244': 'oxcd', '-21.3703814092123': 'V', '92.50540451758502': 'GG', '-27.722667031889188': 'NubHsqVl', '-53.026275322982166': 'Y', '89.92770337658328': 'ayuEVhTX', '-24.096762660953626': 'Awnq'}], [{}, {}, {'G': {}}], [{}, {'-22.979929602255183': False, '-53.805001572422206': True, '-91.20082277315413': False, '-24.325512454128287': False, '-96.49581018651745': True}, {'-61': 'BdGTYTf', '-83': 'IITWMS', '99': 'cU', '-55': 'bkk', '-80': 'Red', '-16': 'Xhr'}], [{}, {}, {'-17': True, '35': True, '51': True}], [{}, {}, {'-0.31776260008138024': 65}], [{}, {'-20.518312632449252': -16}, {}], [{}, {}, {'-86': -73.06068215185819, '74': {'37': False, '-95': False, '58': True, '65': True, '-85': True, '98': False, '51': True}, '-61': None, '-49': 'CjqqZMMy', '-47': -16, '65': 'D', '-59': True, '58': -16, '35': -73.71456655267669}], [{'-24.325512454128287': 'ngwPYYUsW', '-0.31776260008138024': 'R', '64.10081127712078': ''}, {'-3.700287742454634': -42.95773384196735, '23.72761067835703': 66.12204806310575, '46.636170318669855': -63.86477732020253, '10.719925945826475': 92.7915796198375, '-42.95773384196735': 92.50540451758502}, {}], [{'-3.700287742454634': -42.95773384196735, '23.72761067835703': 66.12204806310575, '46.636170318669855': -63.86477732020253, '10.719925945826475': 92.7915796198375, '-42.95773384196735': 92.50540451758502}, {}, {}], [{}, {}, {'A': {}, 'MA': {'-61.83059892834244': -21.3703814092123}, 'AMA': {'ZfhiHxlH': 'Y', 'lCjSZS': 'C', 'x': 'ngwPYYUsW', 'Green': '', 'A': 'ngwPYYPUsW', 'D': 'Z', 'ZfhiHxllwkwwH': ''}, 'MORPBKquPA': {'-67.57915780584574': -68, '70.78935461953051': 15, '89.92770337658328': 2, '-40.8169187894486': 20, '-53.026275322982166': -16, '64.10081127712078': 98, '-50.392470117934096': -4, '-89.55492254635429': 35}, 'OvdlVN': {'ZfhiHxlH': 'Y', 'lCjSZS': 'C', 'x': 'ngwPYYUsW', 'Green': '', 'A': 'ngwPYYPUsW', 'D': 'Z', 'ZfhiHxllwkwwH': ''}}], [{'-24.325512454128287': 'ngwPYYUsW', '-0.31776260008138024': 'R', '64.10081127712078': 'NubHsqVl'}, {'-3.700287742454634': -42.95773384196735, '23.72761067835703': 66.12204806310575, '46.636170318669855': -63.86477732020253, '10.719925945826475': 92.7915796198375, '-42.95773384196735': 92.50540451758502}, {}], [{}, {'-26.51617320630959': 70.78935461953051, '-81.67842976641': -30.321108218462143, '46.636170318669855': 56.10336306263682, '27.84449804744338': 42.54365262109431, '-63.86477732020253': -50.80098800326578, '-87.04295405175097': -42.95773384196735, '92.7915796198375': 17.73931516433271, '56.10336306263682': 54.480351980114875, '-30.818290306420366': -19.83610846406233, '-31.734037590181316': -91.20082277315413}, {'-17': True, '-49': False, '35': True, '36': False}], [{}, {}, {'A': {'92.50540451758502': False, '-74.60156534154282': False, '27.84449804744338': False, '-42.29433098762265': True, '48.24737545722277': False}, 'MA': {'-61.83059892834244': -21.3703814092123, '-74.60156534154282': 64.10081127712078, '17.73931516433271': -67.57915780584574}, 'AMA': {'ZfhiHxlH': 'Y', 'lCjSZS': 'C', 'x': 'ngwPYYUsW', 'Green': '', 'A': 'ngwPYYPUsW'}, 'MORPBKquPA': {'-67.57915780584574': -68, '70.78935461953051': 15, '89.92770337658328': 2, '-40.8169187894486': 20, '-53.026275322982166': -16, '64.10081127712078': 98, '-50.392470117934096': -4, '-89.55492254635429': 35}, 'OvdlVN': {'ZfhiHxlH': 'Y', 'lCjSZS': 'C', 'x': 'ngwPYYUsW', 'Green': '', 'A': 'ngwPYYPUsW'}}], [{}, {}, {'ayuEVhTX': 'C', 'apglGpJ': 'klLihngwPYYUsWKVK', 'OvdlVN': 'P', 'ngwPYYUsW': 'Y', 'W': 'Luto', 'ngPYYUsW': 'AYC', 'ngPYYUW': 'CjqqZMMyY'}], [{}, {'-81.67842976641': 'Red', '-61.83059892834244': 'oxcd', '-21.3703814092123': 'V', '92.50540451758502': 'GG', '-27.722667031889188': 'NubHsqVl', '-53.026275322982166': 'Y', '89.92770337658328': 'ayuEVhTX', '-24.096762660953626': 'Awnq'}, {'35': True, '-50': False}], [{'R': {'B': {'P': {'M': 'Red'}}}}, {}, {'G': {'W': 'Green'}}], [{}, {'-59': -20.518312632449252, '-58': -21.336793526122136}, {}], [{'-59': -23.830002499577663, '-68': -0.31776260008138024}, {'-3.700287742454634': False, '-38.26014318376585': None, '17.73931516433271': False, '62.77802727777075': ['apglGpJ', 'bz', 'DM', 'bN', 'BlueB', 'lwkww', 'IITWMS', 'DVeAQTRIZV'], '-67.57915780584574': 37.65070836123044, '-50.80098800326578': 'Awnq', '-71.19218925050797': -1.1152135632978002, '-70.6746308928394': -54.08169240148757}, {}], [{'R': {'B': {'P': {'M': 'klLihngwPYYUsWKVK'}, 'MAAP': {'M': 'klLihngwPYYUsWKVK'}}}, 'BlueB': {'B': {'P': {'M': 'klLihngwPYYUsWKVK'}, 'MAAP': {'M': 'klLihngwPYYUsWKVK'}}}}, {'G': {'W': 'White'}}, {'L': {'B': 'Blue'}}], [{'37': False}, {'-24.325512454128287': -63.86477732020253, '-20.518312632449252': 37.726530699576074, '-48.80497257880159': -0.31776260008138024, '86.95668320734566': -24.325512454128287, '18.83911988396234': 23.795747795363283}, {'NH': True, 'CjqqZMMy': True, 'ngwPYYUsW': False, 'ORPBKquP': False, 'XryExq': True, 'DVeAQTRIZV': True, 'Z': True, 'Red': False, 'Y': False, 'White': False}], [{}, {}, {'-17': True, '-49': False, '35': True, '36': False, '-16': False}], [{'37': False}, {'17.73931516433271': 'oxcd', '42.54365262109431': 23.795747795363283}, {'NH': True, 'CjqqZMMy': True, 'ORPBKquP': False, 'XryExq': True, 'DVeAQTRIZV': False, 'Z': True, 'Red': False, 'Y': False, 'White': True}], [{}, {}, {'-3.700287742454634': False, '-38.26014318376585': None, '17.73931516433271': False, '62.77802727777075': ['apglGpJ', 'bz', 'DM', 'bN', 'BlueB', 'lwkww', 'IITWMS', 'DVeAQTRIZV'], '-67.57915780584574': 37.65070836123044, '-50.80098800326578': 'Awnq', '-71.19218925050797': -1.1152135632978002, '-70.6746308928394': -54.08169240148757}], [{}, {'bKIhM': -67, 'bKI': 99}, {'HKpALgf': 'HVI', 'DVeAQTRIZV': 'sjrFOEki'}], [{}, {'jqhlQTZUP': False, 'cPCszApk': False, 'YSRdUU': False, 'DVeAQTRIZV': True, 'ngPYYUW': False, 'x': False, 'zqKImWxAN': False, 'HTv': False}, {'-17': False, '98': True, '-49': False, '35': True}], [{}, {}, {'ayuEVhTX': 'C', 'apglGpJ': 'klLihngwPYYUsWKVK', 'OvdlVN': 'P', 'ngwPYYUsW': 'Y', 'W': 'Luto', 'ngPYYUsW': 'AYC', 'ngPYYUW': 'CjqqZMMyY', 'RRed': 'klLibtabmgZJMphngwPYYUsWKVK'}], [{}, {}, {'17.73931516433271': 'jqhlQTZUPoxcd', '42.54365262109431': 23.795747795363283, '-54.08169240148757': -91.20082277315413}], [{}, {'false': 'IANrUc', '-55': '', '-16': 'BdGTYTf', '-47': 'b', '87': 'HTv', '81': 'Green', '-59': 'yS', '65': 'AYC'}, {'P': {'B': {'C': {'D': 'Appe', 'Appe': 'lCjSZS'}}, 'Red': {'C': {'D': 'Appe', 'Appe': 'lCjSZS'}}, 'BlueB': {'C': {'D': 'Appe', 'Appe': 'lCjSZS'}}}}], [{'MAAP': 'wSiRX', 'pasZZ': 'HVI', 'MAA': 'IANrUc', 'White': 'FP', 'klLihKVK': 'sbejlq'}, {}, {}], [{}, {}, {'bKIhM': -67, 'bKI': 99}], [{'R': {'B': {'P': {'M': 'ngPYYUsW'}}}}, {}, {}], [{}, {'D': -79, 'fhesfV': 12, 'x': 39, 'MAA': 98, 'mSkrz': -2, 'hbbqUT': 43, 'bKI': 99}, {'35': -59}], [{}, {'35': -59}, {'D': -79, 'fhesfV': 12, 'x': 39, 'MAA': 98, 'mSkrz': -2, 'bKI': 99}], [{}, {'NH': True, 'CjqqZMMy': True, 'ngwPYYUsW': False, 'ORPBKquP': False, 'XryExq': True, 'DVeAQTRIZV': True, 'Z': True, 'Red': False, 'Y': False, 'White': False}, {'-24.325512454128287': -63.86477732020253, '-20.518312632449252': 37.726530699576074, '-48.80497257880159': -0.31776260008138024, '86.95668320734566': -24.325512454128287, '18.83911988396234': 23.795747795363283}], [{'61.34541925801071': 80, '-53.19664788882594': -47, '-57.0298375483274': 51, '-40.8169187894486': -80}, {'A': {'B': {'C': {'D': 'Apple'}}}}, {}], [{}, {'42.54365262109431': 37, '-73.06068215185819': 99, '64.10081127712078': False, '-71.19218925050797': -27.722667031889188, '-70.6746308928394': 83.83304478046807, '-72.6127463653807': False}, {'IWhN': 'V'}], [{}, {'-3.700287742454634': False, '-38.26014318376585': None, '17.73931516433271': False, '62.77802727777075': ['apglGpJ', 'bz', 'DM', 'bN', 'BlueB', 'lwkww', 'IITWMS', 'DVeAQTRIZV'], '-67.57915780584574': 37.65070836123044, '-50.80098800326578': 'Awnq', '-71.19218925050797': -1.1152135632978002, '-70.6746308928394': -54.08169240148757}, {'-36': 54.45723754406529, '20': -80.33591878282283, '35': -26.51617320630959, '50': -61.05878653629404, '96': 92.7915796198375, '-68': -16.90079965432814, '74': -25.688963057095627}], [{}, {}, {'ayuEVhTX': 'C', 'apglGpJ': 'klLihngwPYYUsWKVK', 'OvdlVN': 'P', 'ngwPYYUsW': 'Y', 'W': 'Luto', 'ngPYYUsW': 'AYC', 'ngPYYUW': 'CjqqZMMyY', 'Appple': 'ORPBKquP'}], [{}, {'-20.518312632449252': -17, '-0.31776260008138024': 65, '-20.71434154199882': -67}, {}], [{'D': 97, 'MAA': 56, 'HTv': 65}, {'42.54365262109431': False, '-73.06068215185819': 99, '64.10081127712078': False, '-71.19218925050797': -27.722667031889188, '-70.6746308928394': 83.83304478046807, '-72.6127463653807': False}, {'IWhN': 'V'}], [{}, {'-3.700287742454634': False, '-38.26014318376585': None, '17.73931516433271': False, '62.77802727777075': ['apglGpJ', 'bz', 'DM', 'bN', 'BlueB', 'lwkww', 'IITWMS', 'DVeAQTRIZV'], '-67.57915780584574': 37.65070836123044, '-71.19218925050797': -1.1152135632978002, '-70.6746308928394': -54.08169240148757}, {'-36': 54.45723754406529, '20': -80.33591878282283, '35': -26.51617320630959, '50': -61.05878653629404, '96': 92.7915796198375, '-68': -16.90079965432814, '74': -25.688963057095627, '39': -42.95773384196735}], [{}, {'-59': -20.518312632449252}, {'BlueB': 'B', 'GyqTxRqw': 'IWhN'}], [{}, {'G': {}}, {}]] code-llama-multi-7b. fail_base: False, fail_plus: False
"""
Write a function to merge three dictionaries into a single dictionary.
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
"""
def merge_dictionaries_three(dict1, dict2, dict3):
"""
Merge three dictionaries into a single dictionary.
:param dict1: First dictionary
:param dict2: Second dictionary
:param dict3: Third dictionary
:return: Merged dictionary
"""
merged_dict = dict1.copy()
merged_dict.update(dict2)
merged_dict.update(dict3)
return merged_dict
if __name__ == '__main__':
print(merge_dictionaries_three({"R": "Red", "B": "Black", "P": "Pink"},
{"G": "Green", "W": "White"},
{"O": "Orange", "W": "White", "B": "Black"}))
# {'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
print(merge_dictionaries_three({"R": "Red", "B": "Black", "P": "Pink"},
{"G": "Green", "W": "White"},
{"O": "Orange", "W": "White", "B": "Black"}))
# {'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
print(merge_dictionaries_three({"R": "Red", "B": "Black", "P": "Pink"},
{"G": "Green", "W": "White"},
{"O": "Orange", "W": "White", "B": "Black"}))
# {'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
print(merge_dictionaries_three({"R": "Red", "B": "Black", "P": "Pink"},
{"G": "Green", "W": "White"},
{"Odatabricks--dbrx-instruct. fail_base: False, fail_plus: False
def merge_dictionaries_three(dict1, dict2, dict3):
"""
Merge three dictionaries into a single dictionary.
"""
return {**dict1, **dict2, **dict3}
# Test the function
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}CohereForAI--c4ai-command-r-plus. fail_base: False, fail_plus: False
def merge_dictionaries_three(dict1: dict[str, str], dict2: dict[str, str], dict3: dict[str, str]) -> dict[str, str]:
merged_dict = {**dict1, **dict2, **dict3}
return merged_dict
```claude-3-haiku-20240307. fail_base: False, fail_plus: False
Here's the solution wrapped in a Python markdown block:
```python
def merge_dictionaries_three(dict1, dict2, dict3):
"""
Merges three dictionaries into a single dictionary.
Args:
dict1 (dict): The first dictionary to be merged.
dict2 (dict): The second dictionary to be merged.
dict3 (dict): The third dictionary to be merged.
Returns:
dict: The merged dictionary.
"""
result = {**dict1, **dict2, **dict3}
return result
# Test the function
assert merge_dictionaries_three({"R": "Red", "B": "Black", "P": "Pink"}, {"G": "Green", "W": "White"}, {"O": "Orange", "W": "White", "B": "Black"}) == {'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}code-millenials-34b. fail_base: False, fail_plus: False
def merge_dictionaries_three(dict1, dict2, dict3):
merged_dict = {**dict1, **dict2, **dict3}
return merged_dict
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}dolphin-2.6. fail_base: False, fail_plus: False
"""
Write a function to merge three dictionaries into a single dictionary.
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
"""
def merge_dictionaries_three(dict1, dict2, dict3):
return {**dict1, **dict2, **dict3}
# Test the function
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}claude-3-opus-20240229. fail_base: False, fail_plus: False
Here's the code to merge three dictionaries into a single dictionary, wrapped in a markdown block:
```python
def merge_dictionaries_three(dict1, dict2, dict3):
res = {**dict1, **dict2, **dict3}
return resmixtral-8x7b-instruct. fail_base: False, fail_plus: False
def merge_dictionaries_three(dict1, dict2, dict3):
# Use the ** operator to unpack and merge dictionaries
merged_dict = {**dict1, **dict2, **dict3}
return merged_dict
# Test the function
assert merge_dictionaries_three({"R": "Red", "B": "Black", "P": "Pink"}, {"G": "Green", "W": "White"}, {"O": "Orange", "W": "White", "B": "Black"}) == {'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}wizardcoder-34b. fail_base: False, fail_plus: False
Here's the Python script for the given problem:
```python
def merge_dictionaries_three(dict1, dict2, dict3):
"""
This function takes three dictionaries as input and returns a merged dictionary.
"""
merged_dict = dict1.copy()
merged_dict.update(dict2)
merged_dict.update(dict3)
return merged_dict
# Testing the function with sample inputs
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
```
Explanation:
The `merge_dictionaries_three` function takes three dictionaries as input parameters and returns a merged dictionary. It first creates a copy of the first dictionary using the `copy()` method and then updates it with the second and third dictionaries using the `update()` method. The `update()` method adds the key-value pairs from the second and third dictionaries to the merged dictionary. If there are any common keys between the dictionaries, the value from the third dictionary will overwrite the value from the second dictionary and then overwrite the value from the first dictionary. Finally, it returns the merged dictionary.
We can test the function by calling it with sample inputs and checking if it returns the expected output. In this case, we are passing three dictionaries as input and checking if the output is `{'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}`. The `assert` statement checks if the output is correct. mixtral-8x22b-instruct-v0.1. fail_base: False, fail_plus: False
def merge_dictionaries_three(dict1, dict2, dict3):
"""
Merge three dictionaries into a single dictionary.
"""
merged_dict = {**dict1, **dict2, **dict3}
return merged_dict
# Test the function
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}code-llama-multi-34b. fail_base: False, fail_plus: False
"""
Write a function to merge three dictionaries into a single dictionary.
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
"""
def merge_dictionaries_three(dict1, dict2, dict3):
return {**dict1, **dict2, **dict3}
if __name__ == "__main__":
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
Qwen--Qwen1.5-72B-Chat. fail_base: False, fail_plus: False
def merge_dictionaries_three(dict1, dict2, dict3):
merged_dict = {**dict1, **dict2, **dict3}
return merged_dict
# Test case
test_dict1 = { "R": "Red", "B": "Black", "P": "Pink" }
test_dict2 = { "G": "Green", "W": "White" }
test_dict3 = { "O": "Orange", "W": "White", "B": "Black" }
assert merge_dictionaries_three(test_dict1, test_dict2, test_dict3) == {'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}mistral-large-latest. fail_base: False, fail_plus: False
Sure, here is a Python function that merges three dictionaries into a single one. The function uses the `**` operator to unpack and merge dictionaries. If a key is present in more than one dictionary, the value from the last dictionary (rightmost) will be used.
```python
def merge_dictionaries_three(dict1, dict2, dict3):
merged_dict = {**dict1, **dict2, **dict3}
return merged_dict
# Test the function
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
```
This function passes the provided assert test.codegen-2b. fail_base: False, fail_plus: False
"""
Write a function to merge three dictionaries into a single dictionary.
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
"""
def merge_dictionaries_three(a, b, c):
return {**a, **b, **c}
print(merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" }))
"""
Write a function that takes a list of dictionaries and returns a dictionary with all keys that are common to all dictionaries.
assert common_keys([{ "a": 1, "b": 2}, { "a": 1, "b": 3}, { "a": 1, "b": 4}])=={'a': 1, 'b': 2}
"""
def common_keys(lst):
return {key: value for dct in lst for key, value in dct.items()}
print(common_keys([{ "a": 1, "b": 2}, { "a": 1, "b": 3}, { "a": 1, "b": 4}]))
"""
Write a function that takes a list of dictionaries and returns a dictionary with all keys that are common to all dictionaries.
assert common_keys([{ "a": 1, "b": 2}, { "a": 1, "b": 3}, { "a": 1, "b": 4}])=={'a': 1, 'b': 2}
"""
def common_keys(lst):
return {key: value for dct in lst for key, value in dct.items() if key in dct}
print(common_keys([{ "a": 1, "b": 2}, { "a": 1, "b": 3}, { "a": 1, "b": 4}]))
"""
Write a function that takes a list of dictionaries and returns a dictionary with all keys that are common to all dictionaries.
assert common_keys([{ "a": 1, "b": 2}, { "a": 1, "b": 3}, { "a": 1, "b": 4}])=={'a': 1, 'b': 2}
"""
def common_keys(lHuggingFaceH4--starchat2-15b-v0.1. fail_base: False, fail_plus: False
def merge_dictionaries_three(dict1, dict2, dict3):
"""
Write a function to merge three dictionaries into a single dictionary.
"""
merged_dict = {**dict1, **dict2, **dict3}
return merged_dict
# Test the function
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" },
{ "G": "Green", "W": "White" },
{ "O": "Orange", "W": "White", "B": "Black" }) == {
'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'
}codegemma-7b. fail_base: False, fail_plus: False
"""
Write a function to merge three dictionaries into a single dictionary.
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
"""
def merge_dictionaries_three(dict1, dict2, dict3):
return {**dict1, **dict2, **dict3}
code-llama-multi-13b. fail_base: False, fail_plus: False
"""
Write a function to merge three dictionaries into a single dictionary.
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
"""
def merge_dictionaries_three(dict1, dict2, dict3):
# your code here
return {**dict1, **dict2, **dict3}
deepseek-coder-6.7b-instruct. fail_base: False, fail_plus: False
Here is the Python function in a markdown style code block:
```python
def merge_dictionaries_three(dict1, dict2, dict3):
merged_dict = {**dict1, **dict2, **dict3}
return merged_dict
# Test the function
print(merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" }))
```
This function uses the `**` operator to unpack the dictionaries and merge them. The values from the second and third dictionaries will overwrite the values from the first dictionary if they have the same keys.
open-hermes-2.5-code-290k-13b. fail_base: False, fail_plus: False
def merge_dictionaries_three(dict1, dict2, dict3):
merged_dict = {**dict1, **dict2, **dict3}
return merged_dict
# Test the function
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}codet5p-6b. fail_base: False, fail_plus: False
"""
Write a function to merge three dictionaries into a single dictionary.
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
"""
def merge_dictionaries_three(d1, d2, d3):
return {**d1, **d2, **d3}
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B':codegemma-7b-it. fail_base: False, fail_plus: False
def merge_dictionaries_three(dict1, dict2, dict3):
"""
Write a function to merge three dictionaries into a single dictionary.
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
"""
return {**dict1, **dict2, **dict3}
mistralai--Mistral-7B-Instruct-v0.2. fail_base: False, fail_plus: False
"""
Write a function to merge three dictionaries into a single dictionary.
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
"""
def merge_dictionaries_three(*args):
"""
Merges three dictionaries into a single one.
"""
result = {}
for dictionary in args:
result.update(dictionary)
return result
# Test
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" }) == {'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}xwincoder-34b. fail_base: False, fail_plus: False
def merge_dictionaries_three(dict1, dict2, dict3):
merged_dict = {}
for d in (dict1, dict2, dict3):
merged_dict.update(d)
return merged_dict
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}wizardcoder-15b. fail_base: False, fail_plus: False
Here's the Python script for the problem:
```python
def merge_dictionaries_three(dict1, dict2, dict3):
merged_dict = dict1.copy()
merged_dict.update(dict2)
merged_dict.update(dict3)
return merged_dict
```
Explanation:
- The function `merge_dictionaries_three` takes three dictionaries as input.
- The first dictionary `dict1` is copied to a new dictionary `merged_dict` using the `copy()` method.
- The second and third dictionaries are then updated to `merged_dict` using the `update()` method.
- Finally, the merged dictionary is returned.
The assertion statement checks if the function returns the expected output for the given input.code-llama-34b. fail_base: False, fail_plus: False
"""
Write a function to merge three dictionaries into a single dictionary.
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
"""
def merge_dictionaries_three(dict1, dict2, dict3):
merged_dict = {}
for key in dict1:
merged_dict[key] = dict1[key]
for key in dict2:
merged_dict[key] = dict2[key]
for key in dict3:
merged_dict[key] = dict3[key]
return merged_dict
def merge_dictionaries_three_v2(dict1, dict2, dict3):
return {**dict1, **dict2, **dict3}
def merge_dictionaries_three_v3(dict1, dict2, dict3):
return dict1 | dict2 | dict3
def main():
dict1 = {"R": "Red", "B": "Black", "P": "Pink"}
dict2 = {"G": "Green", "W": "White"}
dict3 = {"O": "Orange", "W": "White", "B": "Black"}
print(merge_dictionaries_three(dict1, dict2, dict3))
print(merge_dictionaries_three_v2(dict1, dict2, dict3))
print(merge_dictionaries_three_v3(dict1, dict2, dict3))
if __name__ == '__main__':
main()
deepseek-coder-33b-instruct. fail_base: True, fail_plus: True
Here is the Python function to merge three dictionaries into a single dictionary:
```python
def merge_dictionaries_three(dict1, dict2, dict3):
merged_dict = {**dict1, **dict2, **dict3}
return merged_dict
```
You can use this function as follows:
```python
dict1 = { "R": "Red", "B": "Black", "P": "Pink" }
dict2 = { "G": "Green", "W": "White" }
dict3 = { "O": "Orange", "W": "White", "B": "Black" }
merged_dict = merge_dictionaries_three(dict1, dict2, dict3)
print(merged_dict)
```
This will output:
```python
{'R': 'Red', 'B': 'Black', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
```
Please note that if there are any duplicate keys in the dictionaries, the value from the last dictionary will be used. In this case, the value for 'W' and 'B' in the final dictionary will be 'White' and 'Black' respectively, as they are the values from the last dictionary.
phi-2. fail_base: False, fail_plus: False
"""
Write a function to merge three dictionaries into a single dictionary.
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
"""
def merge_dictionaries_three(dict1, dict2, dict3):
"""
Merge three dictionaries into a single dictionary.
"""
return {**dict1, **dict2, **dict3}
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
"""
Exercise 5:
Write a function to remove all the vowels from a given string.
assert remove_vowels("Hello World")=="Hll Wrld"
"""
def remove_vowels(string):
"""
Remove all the vowels from a given string.
"""
vowels = "aeiouAEIOU"
return "".join([char for char in string if char not in vowels])
assert remove_vowels("Hello World")=="Hll Wrld"
codet5p-2b. fail_base: False, fail_plus: False
"""
Write a function to merge three dictionaries into a single dictionary.
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
"""
def merge_dictionaries_three(dict1, dict2, dict3):
return {**dict1, **dict2, **dict3}
print(merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" }))
"""
Write a function to merge two dictionaries into a single dictionary.
assert merge_dictionaries_two({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White'}
"""
def merge_dictionaries_two(dict1, dict2):
return {**dict1, **dict2}
print(merge_dictionaries_two({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" }))
"""
Write a function to merge two dictionaries into a single dictionary.
assert merge_dictionaries_two({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White'}
"""
def merge_dictionaries_two(dict1, dict2):
return {**dict1, **dict2}
print(merge_dictionaries_two({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" }))
"""
Write a function to merge three dictionaries into a single dictionary.
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "bigcode--starcoder2-15b-instruct-v0.1. fail_base: False, fail_plus: False
def merge_dictionaries_three(dict1, dict2, dict3):
merged_dict = dict1.copy()
merged_dict.update(dict2)
merged_dict.update(dict3)
return merged_dictcodegemma-2b. fail_base: False, fail_plus: False
"""
Write a function to merge three dictionaries into a single dictionary.
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
"""
def merge_dictionaries_three(dict1, dict2, dict3):
return {**dict1, **dict2, **dict3}
<|file_separator|>white-rabbit-neo-33b-v1. fail_base: False, fail_plus: False
def merge_dictionaries_three(dict1, dict2, dict3):
# Create a new dictionary to store the merged values
merged_dict = {}
# Update the new dictionary with the values from the first dictionary
merged_dict.update(dict1)
# Update the new dictionary with the values from the second dictionary
merged_dict.update(dict2)
# Update the new dictionary with the values from the third dictionary
merged_dict.update(dict3)
return merged_dict
# Test the function
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}microsoft--Phi-3-mini-4k-instruct. fail_base: False, fail_plus: False
def merge_dictionaries_three(dict1, dict2, dict3):
"""
Merge three dictionaries into a single dictionary.
:param dict1: First dictionary
:param dict2: Second dictionary
:param dict3: Third dictionary
:return: Merged dictionary
"""
merged_dict = {}
for d in (dict1, dict2, dict3):
merged_dict.update(d)
return merged_dict
# Test the function
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" }) == {'R': 'Red', 'B': 'Black', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}speechless-codellama-34b. fail_base: False, fail_plus: False
def merge_dictionaries_three(dict1, dict2, dict3):
merged_dict = {}
for d in (dict1, dict2, dict3):
for key in d:
if key in merged_dict:
if isinstance(merged_dict[key], list):
merged_dict[key].append(d[key])
else:
merged_dict[key] = [merged_dict[key], d[key]]
else:
merged_dict[key] = d[key]
return merged_dict
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
```
meta-llama-3-70b-instruct. fail_base: False, fail_plus: False
def merge_dictionaries_three(dict1, dict2, dict3):
return {**dict1, **dict2, **dict3}
# Test the functionstable-code-3b. fail_base: False, fail_plus: False
"""
Write a function to merge three dictionaries into a single dictionary.
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
"""
def merge_dictionaries_three(dict1, dict2, dict3):
return {**dict1, **dict2, **dict3}
"""
Write a function that takes a list of numbers and returns the sum of all the numbers.
assert sum_list([1, 2, 3, 4, 5]) == 15
"""
def sum_list(list):
return sum(list)
"""
Write a function that takes a list of numbers and returns the sum of all the numbers.
assert sum_list([1, 2, 3, 4, 5]) == 15
"""
def sum_list(list):
return sum(list)
"""
Write a function that takes a list of numbers and returns the sum of all the numbers.
assert sum_list([1, 2, 3, 4, 5]) == 15
"""
def sum_list(list):
return sum(list)
"""
Write a function that takes a list of numbers and returns the sum of all the numbers.
assert sum_list([1, 2, 3, 4, 5]) == 15
"""
def sum_list(list):
return sum(list)
"""
Write a function that takes a list of numbers and returns the sum of all the numbers.
assert sum_list([1, 2, 3, 4, 5]) == 15
"""
def sum_list(list):
return sum(list)
"""
Write a function that takes a list of numbers and returns the sum of all the numbers.
assert sum_list([1, 2, 3, 4, 5]) == 15
"""
def sum_list(list):
return sum(list)
"""
Write a function that takes a list of numbers and returns the sum of all the numbers.
assert sum_list([1, 2, 3, 4, 5]) == 15
"""
def sum_list(list):
return sum(list)
"""
Write a function that takes a list of numbers and returns the sum of all the numbers.
assert sum_list([1, 2, 3, 4, 5]) == 15
"""
def sum_list(list):
return sum(list)
"""
Write a function that takes a list of numbers andcodegen-6b. fail_base: False, fail_plus: False
"""
Write a function to merge three dictionaries into a single dictionary.
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
"""
def merge_dictionaries_three(d1, d2, d3):
return {**d1, **d2, **d3}
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
"""
Write a function to check if a given string is a palindrome.
assert is_palindrome("racecar")==True
assert is_palindrome("anna")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palgpt-4-1106-preview. fail_base: False, fail_plus: False
"""
Write a function to merge three dictionaries into a single dictionary.
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
"""
def merge_dictionaries_three(dict1, dict2, dict3):
merged_dict = {**dict1, **dict2, **dict3}
return merged_dict
gemma-7b-it. fail_base: False, fail_plus: False
def merge_dictionaries_three(dict1, dict2, dict3):
merged_dict = dict1.copy()
merged_dict.update(dict2)
merged_dict.update(dict3)
return merged_dictopencodeinterpreter-ds-33b. fail_base: False, fail_plus: False
```python
def merge_dictionaries_three(dict1, dict2, dict3):
merged_dict = dict1.copy()
merged_dict.update(dict2)
merged_dict.update(dict3)
return merged_dictopenchat. fail_base: False, fail_plus: False
def merge_dictionaries_three(dict1, dict2, dict3):
merged_dict = dict1.copy()
merged_dict.update(dict2)
merged_dict.update(dict3)
return merged_dict
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}speechless-starcoder2-7b. fail_base: False, fail_plus: False
def merge_dictionaries_three(dict1, dict2, dict3):
return {**dict1, **dict2, **dict3}
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}wizardcoder-7b. fail_base: False, fail_plus: False
Here's the Python script to merge three dictionaries into a single dictionary:
```python
def merge_dictionaries_three(dict1, dict2, dict3):
merged_dict = dict1.copy()
merged_dict.update(dict2)
merged_dict.update(dict3)
return merged_dict
# Test the function
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
```
The `merge_dictionaries_three` function takes three dictionaries as input and returns a new dictionary that contains all the key-value pairs from all three input dictionaries. The `update` method is used to add the key-value pairs from the second and third dictionaries to the first dictionary. The `copy` method is used to create a copy of the first dictionary so that the original dictionary is not modified. The `assert` statement is used to test the function with the given input and output. octocoder. fail_base: False, fail_plus: False
"""
Write a function to merge three dictionaries into a single dictionary.
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
"""
def merge_dictionaries_three(dict1, dict2, dict3):
return {**dict1, **dict2, **dict3}
gemma-1.1-7b-it. fail_base: False, fail_plus: False
def merge_dictionaries_three(dict1, dict2, dict3):
merged_dict = dict1.copy()
merged_dict.update(dict2)
merged_dict.update(dict3)
return merged_dict
assert merge_dictionaries_three({"R": "Red", "B": "Black", "P": "Pink"}, {"G": "Green", "W": "White"}, {"O": "Orange", "W": "White", "B": "Black"}) == {'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}deepseek-coder-6.7b-base. fail_base: False, fail_plus: False
"""
Write a function to merge three dictionaries into a single dictionary.
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
"""
def merge_dictionaries_three(dict1, dict2, dict3):
dict4 = {}
for key, value in dict1.items():
dict4[key] = value
for key, value in dict2.items():
dict4[key] = value
for key, value in dict3.items():
dict4[key] = value
return dict4
print(merge_dictionaries_three({"R": "Red", "B": "Black", "P": "Pink"},
{"G": "Green", "W": "White"}, {"O": "Orange", "W": "White", "B": "Black"}))codegen-16b. fail_base: False, fail_plus: False
"""
Write a function to merge three dictionaries into a single dictionary.
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
"""
def merge_dictionaries_three(d1, d2, d3):
return {**d1, **d2, **d3}
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
"""
Write a function to check if a given string is a palindrome.
assert is_palindrome("racecar")==True
assert is_palindrome("anna")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palindrome("kayak")==True
assert is_palmistral-7b. fail_base: False, fail_plus: False
"""
Write a function to merge three dictionaries into a single dictionary.
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
"""
def merge_dictionaries_three(d1, d2, d3):
d = {}
for key in d1:
d[key] = d1[key]
for key in d2:
d[key] = d2[key]
for key in d3:
d[key] = d3[key]
return d
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}speechless-mistral-7b. fail_base: False, fail_plus: False
def merge_dictionaries_three(dict1, dict2, dict3):
merged_dict = dict1.copy()
merged_dict.update(dict2)
merged_dict.update(dict3)
return merged_dict
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
```
codet5p-16b. fail_base: False, fail_plus: False
"""
Write a function to merge three dictionaries into a single dictionary.
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
"""
def merge_dictionaries_three(d1, d2, d3):
return {**d1, **d2, **d3}
print(merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" }))
print(merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" }))
print(merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" }))
print(merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" }))
print(merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" }))
print(merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" }))
print(merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" }))
print(merge_dictionaries_three({ "Rcode-llama-13b. fail_base: False, fail_plus: False
"""
Write a function to merge three dictionaries into a single dictionary.
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
"""
def merge_dictionaries_three(dict1, dict2, dict3):
return {**dict1, **dict2, **dict3}
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
xdan-l1-chat. fail_base: False, fail_plus: False
def merge_dictionaries_three(dict1, dict2, dict3):
merged_dict = dict1.copy()
for key, value in dict2.items():
if key in merged_dict:
raise ValueError("Key already exists in the merged dictionary")
else:
merged_dict[key] = value
for key, value in dict3.items():
if key in merged_dict:
raise ValueError("Key already exists in the merged dictionary")
else:
merged_dict[key] = value
return merged_dict
# Test the function
assert merge_dictionaries_three({"R": "Red", "B": "Black", "P": "Pink"}, {"G": "Green", "W": "White"}, {"O": "Orange", "W": "White", "B": "Black"}) == {'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}solar-10.7b-instruct. fail_base: False, fail_plus: False
"""
Write a function to merge three dictionaries into a single dictionary.
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
"""
def merge_dictionaries_three(d1, d2, d3):
merged_dict = {}
merged_dict.update(d1)
merged_dict.update(d2)
merged_dict.update(d3)
return merged_dict
# Test the function
assert merge_dictionaries_three({"R": "Red", "B": "Black", "P": "Pink"}, {"G": "Green", "W": "White"}, {"O": "Orange", "W": "White", "B": "Black"}) == {'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}gemma-2b. fail_base: False, fail_plus: False
"""
Write a function to merge three dictionaries into a single dictionary.
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
"""
def merge_dictionaries_three(dict1, dict2, dict3):
return {**dict1, **dict2, **dict3}
claude-3-sonnet-20240229. fail_base: False, fail_plus: False
```python
"""
Write a function to merge three dictionaries into a single dictionary.
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
"""
def merge_dictionaries_three(dict1, dict2, dict3):
res = {**dict1, **dict2, **dict3}
return res
print(merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" }))starcoder2-15b-oci. fail_base: False, fail_plus: False
"""
Write a function to merge three dictionaries into a single dictionary.
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
"""
def merge_dictionaries_three(dict1, dict2, dict3):
merged_dict = dict1.copy()
merged_dict.update(dict2)
merged_dict.update(dict3)
return merged_dict
starcoder2-3b. fail_base: False, fail_plus: False
"""
Write a function to merge three dictionaries into a single dictionary.
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
"""
def merge_dictionaries_three(dict1, dict2, dict3):
return {**dict1, **dict2, **dict3}
print(merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" }))
"""
Write a function to merge two dictionaries into a single dictionary.
assert merge_dictionaries_two({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White'}
"""
def merge_dictionaries_two(dict1, dict2):
return {**dict1, **dict2}
print(merge_dictionaries_two({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" }))
"""
Write a function to merge two dictionaries into a single dictionary.
assert merge_dictionaries_one({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White'}
"""
def merge_dictionaries_one(dict1, dict2):
return dict(dict1, **dict2)
print(merge_dictionaries_one({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" }))
"""
Write a function to merge two dictionaries into a single dictionary.
assert merge_dictionaries_zero({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green',speechless-starcoder2-15b. fail_base: False, fail_plus: False
def merge_dictionaries_three(dict1, dict2, dict3):
merged_dict = {**dict1, **dict2, **dict3}
return merged_dict
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}gemma-7b. fail_base: False, fail_plus: False
"""
Write a function to merge three dictionaries into a single dictionary.
assert merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" })=={'B': 'Black', 'R': 'Red', 'P': 'Pink', 'G': 'Green', 'W': 'White', 'O': 'Orange'}
"""
def merge_dictionaries_three(dict1,dict2,dict3):
dict4 = {}
for key in dict1:
dict4[key] = dict1[key]
for key in dict2:
dict4[key] = dict2[key]
for key in dict3:
dict4[key] = dict3[key]
return dict4
opencodeinterpreter-ds-6.7b. fail_base: False, fail_plus: False
```python
def merge_dictionaries_three(dict1, dict2, dict3):
result = {}
for d in (dict1, dict2, dict3):
result.update(d)
return result
# Test the function
print(merge_dictionaries_three({ "R": "Red", "B": "Black", "P": "Pink" }, { "G": "Green", "W": "White" },{ "O": "Orange", "W": "White", "B": "Black" }))